UVa 11100 The Trip, 2007 (题意+贪心)

Posted 2020-09-03 dwtfukgv

题意：有n个包，其中小包可以装到大的包里，包的大小用数字进行表示，求最小的装包数量。

析：这个题的题意不太好理解，主要是有一句话难懂，意思是让每个最大包里的小包数量的最大值尽量小，所以我们就不能随便输出了，

我们先求出最少多少包，这个肯定是相同包的的最大数目了，然后输出时用等差输出，这样就能保证题目的要求。

代码如下：

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
//#include <unordered_map>
//#include <unordered_set>
#define debug() puts("++++");
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;

typedef long long LL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const double inf = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e4 + 5;
const int mod = 2000;
const int dr[] = {-1, 1, 0, 0};
const int dc[] = {0, 0, 1, -1};
const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline bool is_in(int r, int c){
    return r >= 0 && r < n && c >= 0 && c < m;
}
int a[maxn];

int main(){
    int kase = 0;
    while(scanf("%d", &n) == 1 && n){
        int ans = 1;
        for(int i = 0; i < n; ++i)  scanf("%d", a + i);
        sort(a, a + n);
        int cnt = 1;
        for(int i = 1; i < n; ++i){
            if(a[i] == a[i-1])  ++cnt;
            else cnt = 1;
            ans = max(ans, cnt);
        }
        if(kase)  puts("");
        ++kase;
        printf("%d\n", ans);
        cnt = 0;
        while(cnt < ans){
            for(int i = cnt; i < n; i += ans)
                if(i == cnt)  printf("%d", a[i]);
                else printf(" %d", a[i]);
            printf("\n");
            ++cnt;
        }
    }
    return 0;
}
//