hdu 5945 Fxx and game 单调队列优化dp
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Fxx and game
Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)
Problem Description
Young theoretical computer scientist Fxx designed a game for his students.
In each game, you will get three integers X,k,t.In each step, you can only do one of the following moves:
1.X=X−i(0<=i<=t).
2.if k|X,X=X/k.
Now Fxx wants you to tell him the minimum steps to make X become 1.
In each game, you will get three integers X,k,t.In each step, you can only do one of the following moves:
1.X=X−i(0<=i<=t).
2.if k|X,X=X/k.
Now Fxx wants you to tell him the minimum steps to make X become 1.
Input
In the first line, there is an integer T(1≤T≤20) indicating the number of test cases.
As for the following T lines, each line contains three integers X,k,t(0≤t≤106,1≤X,k≤106)
For each text case,we assure that it‘s possible to make X become 1。
As for the following T lines, each line contains three integers X,k,t(0≤t≤106,1≤X,k≤106)
For each text case,we assure that it‘s possible to make X become 1。
Output
For each test case, output the answer.
Sample Input
2
9 2 1
11 3 3
Sample Output
4
3
Source
#pragma comment(linker, "/STACK:1024000000,1024000000") #include<iostream> #include<cstdio> #include<cmath> #include<string> #include<queue> #include<algorithm> #include<stack> #include<cstring> #include<vector> #include<list> #include<set> #include<map> using namespace std; #define ll long long #define pi (4*atan(1.0)) #define eps 1e-14 #define bug(x) cout<<"bug"<<x<<endl; const int N=1e6+10,M=1e6+10,inf=2e9; const ll INF=1e18+10,mod=2147493647; int dp[N]; int q[N]; int main() { int T; scanf("%d",&T); while(T--) { memset(dp,0,sizeof(dp)); int n,k,t; scanf("%d%d%d",&n,&k,&t); int l=1,r=1; dp[1]=0; q[r++]=1; for(int i=2;i<=n;i++) { dp[i]=inf; while(l<r&&q[l]<i-t)l++; if(l<r)dp[i]=dp[q[l]]+1; if(i%k==0)dp[i]=min(dp[i/k]+1,dp[i]); while(l<r&&dp[q[r-1]]>=dp[i])r--; q[r++]=i; } //for(int i=1;i<=n;i++) // printf("%d ",dp[i]); //printf("\n"); printf("%d\n",dp[n]); } return 0; }
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