将url的查询参数解析成字典对象

Posted 2020-09-01 百里登风

1、先截取请求参数字符串；

2、使用decodeURIComponent函数进行解码；

3、正则匹配出参数对象；

function getQueryObject(url) { 
    url = url == null ? window.location.href : url; 
    var search = url.substring(url.lastIndexOf("?") + 1); 
    var obj = {}; 
    var reg = /([^?&=]+)=([^?&=]*)/g; 
    search.replace(reg, function (rs, key, value) { 
        var name = decodeURIComponent(key); 
        var val = decodeURIComponent(value);                
        val = String(val); 
        obj[name] = val; 
        return rs; 
    }); 
    return obj; 
}