C#如何获取指定周的日期范围
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1. 不允许跨年
1) 第一周的第一天从每年的第一天开始,最后一周的最后一天为每年的最后一天。
1 static void Main(string[] args)
2 {
3 DateTime first, last;
4 int[] years = new int[] { 2015, 2016, 2017, 2018 };
5 int[] weeks = new int[] { 1, 52, 53 };
6 foreach (int y in years)
7 {
8 foreach (int w in weeks)
9 {
10 bool result = CalcWeekDay(y, w, out first, out last);
11 Console.WriteLine("{0}第{1}周({2:yyyy-MM-dd} ~ {3:yyyy-MM-dd}) --{4}", y, w, first, last, result);
12 }
13 Console.WriteLine();
14 }
15 }
16
17 public static bool CalcWeekDay(int year, int week, out DateTime first, out DateTime last)
18 {
19 first = DateTime.MinValue;
20 last = DateTime.MinValue;
21 //年份超限
22 if (year < 1700 || year > 9999) return false;
23 //周数错误
24 if (week < 1 || week > 53) return false;
25 //指定年范围
26 DateTime start = new DateTime(year, 1, 1);
27 DateTime end = new DateTime(year, 12, 31);
28 int startWeekDay = (int)start.DayOfWeek;
29
30 if (week == 1)
31 {
32 first = start;
33 last = start.AddDays(6 - startWeekDay);
34 }
35 else
36 {
37 //周的起始日期
38 first = start.AddDays((7 - startWeekDay) + (week - 2) * 7);
39 last = first.AddDays(6);
40 if (last > end)
41 {
42 last = end;
43 }
44 }
45 return (first <= end);
2) 程序执行结果
2. 允许跨年
1) 每年的尾周剩余天数计入下一年第一周。
1 public static bool CalcWeekDay(int year, int week, out DateTime first, out DateTime last)
2 {
3 first = DateTime.MinValue;
4 last = DateTime.MinValue;
5 //年份超限
6 if (year < 1700 || year > 9999) return false;
7 //周数错误
8 if (week < 1 || week > 53) return false;
9 //指定年范围
10 DateTime start = new DateTime(year, 1, 1);
11 DateTime end = new DateTime(year, 12, 31);
12 int startWeekDay = (int)start.DayOfWeek;
13 //周的起始日期
14 first = start.AddDays((7 - startWeekDay) + (week - 2) * 7);
15 last = first.AddDays(6);
16 //结束日期跨年
17 return (last <= end);
18 }
2) 程序执行结果
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