sql server 2000数据服务器在电脑上找不到，桌面右下角没有图标。

Posted 2023-04-05

看看这里有没有，「开始」菜单\程序\Microsoft SQL Server\服务管理器
如果开始菜单有，那就启动试试。
如果开始菜单没有，那去 管理工具-服务-MSSQLSERVER 和 SQLSERVERAGENT 看看这两个服务有没有，
没有的话，说明你可能没正常安装。 参考技术A 开始菜单-程序里如果没有的话，可能是你安装中出现错误，建议电脑在刚装完操作系统时就安装SQL SERVER 2000，那样不容易出错。 参考技术B 开始菜单-程序里，如果没有说明你没装嘛...

???Sql Server???SQL SERVER ????????????

?????????int   with   ??????   serve   span   ??????   inner   --   blog   

??????:???Sql Server???SQL SERVER ????????????

??????SQL SERVER 2005?????????????????????????????????????????????SQL SERVER 2005???????????????CTE?????????????????????CTE?????????????????????

??????CTE??????????????????Common Table Expression ???SQL SERVER 2005????????????????????????????????????

#??????????????????

1???sql

 1 Create table GroupInfo([Id] int,[GroupName] nvarchar(50),[ParentGroupId] int)
 2 
 3 Insert GroupInfo
 4 
 5 select 0,??????????????????,null union all
 6 
 7 select 1,??????????????????,0 union all
 8 select 2,??????????????????,1 union all
 9 select 3,??????????????????,1 union all
10 select 4,????????????????????????,2 union all
11 select 5,????????????????????????,2 union all
12 select 6,????????????????????????,3 union all
13 select 7,????????????????????????,3 union all
14 
15 select 8, ???????????????,0 union all
16 select 9, ?????????????????????,8 union all
17 select 10,????????????????????????,8 union all
18 select 11,???????????????????????????,9 union all
19 select 12,???????????????????????????,9 union all
20 select 13,??????????????????????????????,10 union all
21 select 14,??????????????????????????????,10 

2????????????

 

#????????????Demo

1???????????????????????????????????????????????????,???????????????????????????

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=1
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.Id=G.ParentGroupId
10 )
11 select * from CTE order by Id

 

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=14
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.ParentGroupId=G.Id
10 )
11 select * from CTE order by Id

2?????????????????????

 1 --??????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select Id,GroupName,ParentGroupId,GroupPath=CAST( GroupName as nvarchar(max)) from GroupInfo where Id=1
 7     union all
 8     select G.*,CAST(CTE.GroupPath+???//???+G.GroupName as nvarchar(max)) as GroupPath from CTE 
 9     inner join GroupInfo as G
10     on CTE.Id=G.ParentGroupId
11 )
12 select * from CTE

 3?????????????????????????????????????????????????????????

 1 --??????id????????????????????????????????????sort??????????????????sort??????????????????????????????????????????????????????
 2 WITH    
 3 CTE
 4 AS 
 5 ( 
 6     SELECT * ,CAST(RIGHT(???000??? + CAST([Id] AS VARCHAR), 3) AS VARCHAR(MAX)) AS sort FROM GroupInfo
 7     WHERE ParentGroupId = 0
 8     UNION ALL
 9     SELECT   GroupInfo.* ,CAST(sort + RIGHT(???000??? + CAST(GroupInfo.[Id] AS VARCHAR),3) AS VARCHAR(MAX)) AS sort
10     FROM CTE
11     INNER JOIN GroupInfo ON CTE.Id = GroupInfo.ParentGroupId
12 )
13 SELECT * FROM CTE ORDER BY sort 

 

4?????????????????????????????????????????????????????????

1 --??????????????????
2 WITH CTE AS (
3     SELECT *,1 AS [Level] FROM GroupInfo WHERE ParentGroupId=0
4     UNION ALL
5     SELECT G.*,CTE.Level+1 FROM GroupInfo as G 
6     JOIN CTE ON CTE.Id =G.ParentGroupId
7 )
8 SELECT * FROM CTE