UVA1449-Dominating Patterns(AC自己主动机)
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AC自己主动机的模板题。须要注意的是,对于每一个字符串,须要利用map将它映射到一个结点上,这样才干按顺序输出结果。
14360841 | 1449 |
php? option=com_onlinejudge&Itemid=8&page=show_problem&problem=4195" style="font-size:13.3333330154419px; margin:0px; padding:0px; color:rgb(153,0,0); text-decoration:none">Dominating Patterns |
Accepted | C++ | 0.146 | 2014-10-16 11:41:35 |
#include<stack> #include<queue> #include<map> #include<set> #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; const int maxn = 150 * 75; const int len = 1111111; const int max_size = 26; char str[155][75]; char _str[len]; struct Trie{ //AC int tr[maxn][max_size]; int fail[maxn]; int val[maxn]; //结果 int sz,root,_max; //出现次数 map<int,int>countx;//计算第i个字符串出现的次数 map<string,int>vis; int index(char c){ return c - 'a'; } int newnode(){ val[sz] = 0; for(int i = 0; i < 26; i++) tr[sz][i] = -1; sz ++; return sz - 1; } void init(){ sz = 0;_max = 0; root = newnode(); countx.clear(); vis.clear(); } void insert(char *s,int id){ int u = root; int n = strlen(s); for(int i = 0; i < n; i++){ int c = index(s[i]); //printf("%d %d\n",u,c); if(tr[u][c] == -1) tr[u][c] = newnode(); u = tr[u][c]; } vis[string(s)] = u; //这个字符串相应的结点编号 //printf("%d\n",u); val[u] ++;//达到这个结点的单词 } void build(){ queue<int>q; fail[root] = root; for(int i = 0; i < 26; i++){ if(tr[root][i] == -1) tr[root][i] = root; else{ fail[tr[root][i]] = root; q.push(tr[root][i]); } } while(!q.empty()){ int now = q.front(); q.pop(); for(int i = 0; i < 26; i++){ if(tr[now][i] == -1) tr[now][i] = tr[fail[now]][i]; else{ fail[tr[now][i]] = tr[fail[now]][i]; q.push(tr[now][i]); } } } } void countt(char *s){ int n = strlen(s); int u = root; for(int i = 0; i < n; i++){ u = tr[u][index(s[i])]; int temp = u; while(temp != root){ if(val[temp]){ //这个结点存在单词 countx[temp]++; //这个结点 _max = max(_max,countx[temp]); } temp = fail[temp]; } } } }; Trie ac; int main(){ int n; while(scanf("%d",&n) && n){ ac.init(); for(int i = 0; i < n; i++){ scanf("%s",str[i]); ac.insert(str[i],i); //插入单词 } //printf("%d\n",ac.sz); ac.build(); scanf("%s",_str); ac.countt(_str); printf("%d\n",ac._max); for(int i = 0; i < n; i++){ if(ac.countx[ac.vis[string(str[i])]] == ac._max) printf("%s\n",str[i]); } } return 0; }
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