day4作业

Posted 2020-08-29 ezway

练习题

一、元素分类

有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。
即： {\'k1\': 大于66的所有值, \'k2\': 小于66的所有值}

二、查找

查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。

    li = ["alec", " aric", "Alex", "Tony", "rain"]

    tu = ("alec", " aric", "Alex", "Tony", "rain") 

    dic = {\'k1\': "alex", \'k2\': \' aric\',  "k3": "Alex", "k4": "Tony"}

 

三、输出商品列表，用户输入序号，显示用户选中的商品

    商品 li = ["手机", "电脑", \'鼠标垫\', \'游艇\']

 

四、购物车

功能要求：

• 要求用户输入总资产，例如：2000
• 显示商品列表，让用户根据序号选择商品，加入购物车
• 购买，如果商品总额大于总资产，提示账户余额不足，否则，购买成功。
• 附加：可充值、某商品移除购物车

?

1 2 3 4 5 6

goods = [     {"name": "电脑", "price": 1999},     {"name": "鼠标", "price": 10},     {"name": "游艇", "price": 20},     {"name": "美女", "price": 998}, ]

 五、用户交互，显示省市县三级联动的选择

?

1 2 3 4 5 6 7 8 9 10 11 12 13

dic = {     "河北": {         "石家庄": ["鹿泉", "藁城", "元氏"],         "邯郸": ["永年", "涉县", "磁县"],     }     "河南": {         ...     }     "山西": {         ...     }   }

答案：

#!usr/bin/evn python
# -*- coding:utf-8 -*-
#1
dic={\'k1\':[],\'k2\':[]}
li=[11,22,33,44,55,66,77,88,99,90]
for i in li:
    if i>=66:
        dic[\'k1\'].append(i)
    else:
        dic[\'k2\'].append(i)
print(dic)




#2


li = ["aleb", " aric", "Alex", "Tony", "rain"]

tu = ("alec", " aric", "Alex", "Tony", "rain")

dic = {\'k1\': "alex", \'k2\': \' aric\', "k3": "Alex", "k4": "Tony"}

for i in li:
    a=i.strip()
    if (a.startswith(\'a\') or a.startswith(\'A\')) and a.endswith(\'c\'):
        print(a)
for j in tu:
    b=j.strip()
    if b.startswith(\'a\') or b.startswith(\'A\') and b.endswith(\'c\'):
        print(\'b-\'+b)

for v in dic.values():

    d=v.strip()
    #print(d,\'-\')
    if (d.startswith(\'a\') or b.startswith(\'A\')) and b.endswith(\'c\'):
        print(\'d-\'+d)



#3


li = ["手机", "电脑", \'鼠标垫\', \'游艇\']
# a={}
# for i,j in enumerate(li,1):
#
#     a[i]=j
#
# num=int(input(\'blabla:\'))
#
# print(a[num])

for i, j in enumerate(li, 1):
    print(i, j)
while 1:

    num = int(input(\'blabla:\'))
    if num > 0 and num <= len(li):

        print(li[num - 1])

    else:
        print(\'null\')




#4


total_money = int(input(\'请输入总金额:  \'))

picked_car = []

picked_money = 0
goods = [

    {"name": "电脑", "price": 1999},

    {"name": "鼠标", "price": 10},

    {"name": "游艇", "price": 20},

    {"name": "美女", "price": 998},

]

goods_name = []
goods_name_price = {}
for i in goods:
    a = i[\'name\']
    b = i[\'price\']

    goods_name.append(a)
    # print(a)
    goods_name_price[a] = b
# print(goods_name_price)

for j, k in enumerate(goods_name, 1):
    print(j, k)
while 1:

    goods_num = input(\'请输入选中商品号，付款请输入【购买】：  \')
    try:
        goods_num = int(goods_num)
    except ValueError:
        goods_num = \'购买\'
    try:
        picked_car.append(goods_name[goods_num - 1])
        picked_money += goods_name_price[goods_name[goods_num - 1]]
    except TypeError:
        pass
    print(picked_money)
    print(picked_car)

    if goods_num == \'购买\' and total_money >= picked_money:
        print(\'购买成功，谢谢惠顾\')
        break
    elif goods_num == \'购买\' and total_money < picked_money:
        user_choice = input(\'您的资金不足，请【充值】或者【移除】购物车内一些商品：\')
        if user_choice == \'充值\':
            print(\'当前余额：\' + total_money)
            total_money += int(input(\'请输入总金额:  \'))
            print(\'充值后金额：\' + total_money)
            continue
        elif user_choice == \'移除\':
            while 1:
                print(picked_car)
                del_choice = input(\'请输入要移除的商品,完事后输出【ok】继续付款：\')
                del picked_car[del_choice]
                print(picked_car)
                if del_choice == \'ok\':
                    break
                continue



#5


dic = {

    "河北": {

        "石家庄": ["鹿泉", "藁城", "元氏"],

        "邯郸": ["永年", "涉县", "磁县"],

    }
}

for i in dic:
    print(i)
    a=dic[i]
usip=str(input(\'输入省份: \'))

for j in a:
    print(j)
    b=dic[i][j]

usip2=str(input(\'输入市: \'))

for k in b:
    print(k)
usip2=str(input(\'输入县: \'))