python输出当前的时间和推到七天前的日期

Posted 2020-06-17

项目发展的需要：（包含时间函数）time datetime

需要当前的日期，并显示出时间轴，然后推出七天前的具体日期

 1 #! /usr/bin/env python
 2 # -*- coding=utf-8 -*-
 3 import re
 4 import time
 5 from datetime import datetime
 6 now = datetime.now()
 7 list = [0,31,28,31,30,31,30,31,31,30,31,30,31]
 8 def judge(year):#判断是否是闰年
 9     if year % 100 == 0 and year % 400 == 0:
10          return 1
11     elif year % 100 != 0 and year % 4 == 0:
12          return 1
13     return 0
14 
15 def GetNowTime():
16     #当前的时间
17     print "Now Time:"
18     print time.time()
19     print time.strftime(‘%Y-%m-%d %H:%M:%S‘,time.localtime(time.time()))
20     # 输出当前的：年月日 承接上面的 now = datetime.now()
21     # y =  now.year
22     # m = now.month
23     # d = now.day
24     #输入年月日：
25     print "input:"
26     y = int (raw_input())
27     m = int (raw_input())
28     d = int (raw_input())
29     # print time.time()
30     # 输出年月日+具体的时间
31     # y =  now.year
32     # m = now.month
33     # d = now.day
34     ymd = judge(y)
35     print "Input Time："
36     print str(y)+"-"+str(m)+"-"+str(d)
37     #如果是闰年，则二月份 要加一
38     list[2] = list[2] + ymd
39     #时间倒退7天
40     if(d>7):
41         d = d-7
42     else:
43         #if it not is Janurary
44         if m!=1:
45             m = m-1
46             d = list[m]+d-7
47         #if it is Janurary
48         else:
49             y = y -1    #年份减去1
50             m = 12      #月份到12月
51             d = d+list[12]-7
52     #恢复二月的原始天数
53     print "eryue: " +str(list [2])
54     list[2] = list[2] - ymd
55     #输出七天七的日期
56     print ‘Seven days ago:‘
57     print str(y)+"-"+str(m)+"-"+str(d)
58 if __name__ == "__main__":
59     GetNowTime()

代码测试：

D:\Python27\python.exe D:/py/Bfun/donghua/test.py
Now Time:
1456717147.79
2016-02-29 11:39:07


input:
2015
03
07
Input Time：
2015-3-7
eryue: 28
Seven days ago:
2015-2-28

input:
2016
03
07
Input Time：
2016-3-7
eryue: 29
Seven days ago:
2016-2-29


input:
2016
01
07
Input Time：
2016-1-7
eryue: 29
Seven days ago:
2015-12-31