492. 构造矩形 Construct the Rectangle

Posted 2020-08-29 Long Long Journey

For a web developer, it is very important to know how to design a web page‘s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won‘t exceed 10,000,000 and is a positive integer
2. The web page‘s width and length you designed must be positive integers. 

给定矩形的面积area，返回矩形的长度L和宽度W，使得L和W的差值最小。

public class Solution {
    public int[] ConstructRectangle(int area) {
		if (area == 0) {
			int[] arr = { };
			return arr;
		}
		int[] result = { area, 1 };
		for(int height = 1; height <= area; height++) {
			if (area % height == 0) {
				int width = area / height;
				if (width < height) {
					break;
				}else if (width - height < result[0] - result[1]) {
					result[0] = width;
					result[1] = height;
				}
			}
		}
		return result;
    }
}

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