383.判断一个字符串是否能够包含另外一个字符串 Ransom Note
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Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false canConstruct("aa", "ab") -> false canConstruct("aa", "aab") -> true
static public bool CanConstruct(string ransomNote, string magazine) {
Dictionary<char, int> d = new Dictionary<char, int>();
char[] mArr = magazine.ToCharArray();
int mArrLength = mArr.Length;
for (int i = 0; i < mArrLength; i++) {
char c = mArr[i];
int v = 0;
if (d.TryGetValue(c, out v)) {
d[c] = v + 1;
} else {
d.Add(c, 1);
}
}
char[] rArr = ransomNote.ToCharArray();
int rArrLength = rArr.Length;
for (int i = 0; i < rArrLength; i++) {
char c = rArr[i];
int v = 0;
if (!d.TryGetValue(c, out v) || v == 0) {
return false;
} else {
d[c] -= 1;
}
}
return true;
}
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