[GraphQL] Create an Input Object Type for Complex Mutations

Posted Answer1215

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了[GraphQL] Create an Input Object Type for Complex Mutations相关的知识,希望对你有一定的参考价值。

When we have certain mutations that require more complex input parameters, we can leverage the Input Object Type in GraphQL. In this video, we’ll learn how to create an Input Object Type and how to add it to a GraphQL Mutation Type.

 

const express     = require(express);
const graphqlHttp = require(express-graphql);
const {
          getVideoById, getVideos, createVideo
      }           = require(./data/index);
const server      = express();
const port        = process.env.PORT || 3000;

const {
          GraphQLSchema, GraphQLObjectType, GraphQLInputObjectType, GraphQLString, GraphQLList, GraphQLInt, GraphQLNonNull, GraphQLBoolean, GraphQLID
      } = require(graphql);

const videoType = new GraphQLObjectType({
    name        : video,
    description : A video on Egghead.io,
    fields      : {
        id       : {
            type        : GraphQLID,
            description : The id of the video
        },
        title    : {
            type        : GraphQLString,
            description : The title of the video
        },
        duration : {
            type        : GraphQLInt,
            description : The duration of the video
        },
        watched  : {
            type        : GraphQLBoolean,
            description : Whether or no the viewer watched the video
        }
    }
});

const videoInputType = new GraphQLInputObjectType({
    name   : videoInput,
    fields : {
        title    : {
            type        : new GraphQLNonNull(GraphQLID),
            description : The title of the video
        },
        duration : {
            type        : new GraphQLNonNull(GraphQLInt),
            description : The duration of the video
        },
        watched  : {
            type : new GraphQLNonNull(GraphQLBoolean)
        }
    }
});

const mutationType = new GraphQLObjectType({
    name        : Mutation,
    description : The root Mutation type,
    fields      : {
        createVideo : {
            type    : videoType,
            args    : {
                video : {
                    type : new GraphQLNonNull(videoInputType),
                },
            },
            resolve : (_, args) => {
                return createVideo(args.video)
            }
        }
    }
});

const queryType = new GraphQLObjectType({
    name        : QueryType,
    description : The root query type,
    fields      : {
        videos : {
            type    : new GraphQLList(videoType),
            resolve : getVideos
        },
        video  : {
            type    : videoType,
            args    : {
                id : {
                    type        : new GraphQLNonNull(GraphQLID),
                    description : The id of the video
                }
            },
            resolve : (_, args) => getVideoById(args.id)
        }
    }
});

const schema = new GraphQLSchema({
    query    : queryType,
    mutation : mutationType
});

server.use(/graphql, graphqlHttp({
                                       schema,
                                       graphiql : true, // use graphiql interface
                                   }));

server.listen(port, () => {
    console.log(`Listening on http`)
})

 

In GraphiQL:

mutation video {
  createVideo(video: {
    title:"GraphQL",
    duration:100,
    watched: false
  }) {
    id,
    title
  }
}

 

以上是关于[GraphQL] Create an Input Object Type for Complex Mutations的主要内容,如果未能解决你的问题,请参考以下文章

VUE UI create 抛 An error occurred vue-apollo.js:60 GraphQL error: ENOENT: no such file or directory

Cannot create a new pixel buffer adaptor with an asset writer input that has already started writing

[GraphQL] Create a GraphQL Schema

Postman测试Graphql 接口测试与报错:Must provide an operation

Postman测试Graphql 接口测试与报错:Must provide an operation

使用 Relay + React Native (create-react-native-app) 时出错:GraphQL 验证错误`未知类型“查看器”。`