将list集合的元素按照添加顺序的倒序进行排列取出

Posted 2020-08-26 Mr_伍先生

1.方法

Collections.reverse(list);

 

 

2.代码示例

/**
     * 从redis中将现场状态的记录全部取出
     * @param aucId
     * @return
     */
    @RequestMapping(value = "/findAllAuctionLocalStatementRecord", method = RequestMethod.POST)
    @ResponseBody
    public List<Object> findAllAuctionLocalStatementRecord(String aucId) {
        if (logger.isDebugEnabled()) {
            logger.debug("findAllAuctionLocalStatementRecord, aucId:{}", aucId);
        }
        
        List<Object> list = redisTemplateListDTO.opsForValue().get("auctionLocalStatement"+aucId);
        Collections.reverse(list);//将list集合倒序排列取出,时间最新的在最上面
        
        return list;
    }