写了一个用java播放音频的代码，运行时总是出现错误！求指点！

Posted 2023-03-28

运行结果：
javax.sound.sampled.UnsupportedAudioFileException: could not get audio input stream from input file
at javax.sound.sampled.Audiosystem.getAudioInputStream(Unknown Source)
at com.music.AePlayWave.run(Demo.java:44)
代码：
package com.music;

import java.io.File;
import java.io.IOException;
import java.util.*;

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.SourceDataLine;
public class Demo

/**
* @param args
*/
public static void main(String[] args)
// TODO Auto-generated method stub
AePlayWave apw = new AePlayWave("e:\\111.wma");
apw.start();



//播放声音的类
class AePlayWave extends Thread

private String filename;
public AePlayWave(String wavfile)
filename = wavfile;


public void run()
File soundFile = new File(filename);

AudioInputStream audioInputStream = null;
try

audioInputStream = AudioSystem.getAudioInputStream(soundFile);

catch (Exception e1)

e1.printStackTrace();
return;


AudioFormat format = audioInputStream.getFormat();
SourceDataLine auline = null;
DataLine.Info info = new DataLine.Info(SourceDataLine.class,format);

try

auline = (SourceDataLine)AudioSystem.getLine(info);
auline.open(format);

catch (Exception e)

e.printStackTrace();
return;


auline.start();
int nBytesRead = 0;
byte[] abData = new byte[1024];

try

while (nBytesRead !=-1)

nBytesRead = audioInputStream.read(abData,0,abData.length);
if (nBytesRead>=0)

auline.write(abData,0,nBytesRead);



catch (Exception e)

e.printStackTrace();
return;
finally
auline.drain();
auline.close();

参考技术A

jdk对音乐文件播放支持不太好，但是sun有专门开发一个音频类播放的框架，叫 jmf，我这就有用jmf写过两个播放器

参考技术B jmf

File file =new File("e:\\111.wma");
Player audioPlayer = Manager.createRealizedPlayer(file.toURL());
//播放
audioPlayer.start();
//停止
audioPlayer.stop();
audioPlayer.close(); 参考技术C 等待解决方案 参考技术D 因为java sound不支持wma

无法播放用 naudio 录制的音频流

【中文标题】无法播放用 naudio 录制的音频流

【英文标题】：Can't play audio stream recorded with naudio

【发布时间】：2015-05-19 20:13:08

【问题描述】：

我尝试将一些音频（在录制单击按钮后）录制到 MemoryStream 中，然后使用 NAudio 在 Visual Studio(WPF) 中播放。我生成了一个 RawSourceWaveStream，它在单击播放按钮时获取 myMemoryStream，但我认为这是在窃听代码。 它不播放...这是我的代码。 我哪里错了？

      namespace RecAndPlay
      
          /// <summary>
          /// Interaction logic for MainWindow.xaml
          /// </summary>
      public partial class MainWindow : Window
      
          public MainWindow()
          
              InitializeComponent();
          


        private WaveIn myWaveIn=null;
        private MemoryStream myMemoryStream = null;
        private WaveOut myWaveOut= null;
        private RawSourceWaveStream myRaw = null;
        private void myRecord(object sender, RoutedEventArgs e)
        

            
                RecordButton.Content = "Stop Rec";
                myWaveIn = new WaveIn();
                myWaveIn.WaveFormat = new WaveFormat(44100, 1);
                myWaveIn.DeviceNumber = 0;
                myWaveIn.DataAvailable += myWaveIn_DataAvailable;
                myMemoryStream = new MemoryStream();
                myWaveIn.StartRecording();
            

        

        void myWaveIn_DataAvailable(object sender, WaveInEventArgs e)
        

            myMemoryStream.Write(e.Buffer, 0, e.BytesRecorded);
        

        private void myPlay(object sender, RoutedEventArgs e)
        

            myWaveOut = new WaveOut();
            myRaw = new RawSourceWaveStream(myMemoryStream, myWaveIn.WaveFormat);
            myWaveOut.Init(myRaw);
            myWaveOut.Play();


        

        private void mtStopRec(object sender, RoutedEventArgs e)
        
            myWaveIn.StopRecording();
            RecordButton.Content = "Record";
        
    

【问题讨论】：

是的，它到了 myWaveOut.Play();但在那之后我什么都不能在这里。当鼠标站在 myRaw 上时，我可以看到它充满了缓冲区，但没有任何反应。

【参考方案1】：

在播放音频之前，您需要将 MemoryStream 上的 Position 设置为 0。另外，请记住，使用此解决方案时，您不应在仍在录制时尝试播放。