LDAP在JAVA中如何模糊查询

Posted 2023-03-28

参考技术A /** * 获得LDAP连接（不通过连接池,直接获得连接） * @return * @throws Exception */ private javax.naming.directory.DirContext getDirContext() throws Exception DirContext ctx = null; java.util.Hashtable env = new java.util.Hashtable(); env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory"); env.put(Context.PROVIDER_URL, "ldap://localhost:389"); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.SECURITY_PRINCIPAL, user); env.put(Context.SECURITY_CREDENTIALS, pwd); ctx = new InitialDirContext(env); return ctx; /** * 返回用户查询接口 * @param DN 查找范围 ou=test,dc=abcd,dc=com * @param filter 过滤条件 cn=* * @param myserach 搜索范围 * @return LDAP标准接口 * @throws Exception */ public javax.naming.NamingEnumeration getFilter(String DN,String filter,int myserach) throws Exception DirContext ctx = getDirContext(); try NamingEnumeration em; SearchControls con = new SearchControls(); con.setSearchScope(myserach); em = ctx.search(DN, filter, con); return em; finally // /** * 设置条件查找 * @param dn 查找的根结点 * @param filter 查找条件 * @param level 查找范围 * @return 返回一个由DN组成的JAVA STRING 列表 * @throws Exception */ public java.util.Vector getfilterNodes(String dn,String filter,int level) throws Exception java.util.Vector ve=new java.util.Vector(); NamingEnumeration em=getFilter(dn,filter,level); while(em!=null && em.hasMoreElements()) SearchResult rs=(SearchResult)em.nextElement(); String db=rs.getName(); if (db.trim().equals("")) ve.add(dn); else ve.add(db+","+dn); return ve; 查看原帖>>

如何在java List中进行模糊查询

比如我有下面这样一个List，里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么？
比如我输入的查询条件为“wang”，那么应该返回只包含employee1的List列表。

List list = new ArrayList();
Employee employee1 = new Employee();
employee1.setName("wangqiang");
employee1.setAge(30);
list.add(employee1);
Employee employee2 = new Employee();
employee2.setName("lisi");
list.add(employee2);
employee2.setAge(25);

方式一：

public List search(String name,List list){
   List results = new ArrayList();
   Pattern pattern = Pattern.compile(name);
   for(int i=0; i < list.size(); i++){
      Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
      if(matcher.matches()){
         results.add(list.get(i));
      }
   }
   return results;
}

上面那个是大小写敏感的，如果要求大小写不敏感，改成：
Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

并且上面那个是精确查询，如果要模糊匹配，matcher.find()即可以进行模糊匹配

public List search(String name,List list){
   List results = new ArrayList();
   Pattern pattern = Pattern.compile(name);
   for(int i=0; i < list.size(); i++){
      Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
      if(matcher.find()){
         results.add(list.get(i));
      }
   }
   return results;
}

方式二：

public class ListLike {

//定义员工类
public class Employee {
private String name;
private int age;
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}

public List list=new ArrayList();

//增加员工
public List addList(String name,int age){
Employee employee1 = new Employee();
employee1.setName(name);
employee1.setAge(age);
list.add(employee1);
return list;
}

//显示所有员工
public void ShowList(){
for(int i=0;i<list.size();i++){
System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());
}
}

//模糊查询
public List likeString(String likename){
for(int i=0;i<list.size();i++){
if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)
list.remove(i);
}
return list;

}

public static void main(String arg[]){
ListLike ll=new ListLike();
ll.addList("wuxiao",13);
ll.addList("wangwang",11);
ll.addList("wanghua",12);
ll.addList("xiaowang",13);
ll.addList("xiaoxiao",13);

ll.likeString("wang");
ll.ShowList();


}

}