jQuery提交form表单

Posted 2020-06-16

<form id="search_form" name="search_form" method="post"> 
      <input type="text" name="username" /> 
</form>

<script type="text/javascript">
	$(function() {
		$(‘#btn‘).bind(‘click‘, function() {
			document.search_form.action = ‘admin/queryAll.do?pid=‘ + pid;  //定义 action,并传參 
			$(‘#search_form‘).submit();
		});
	})
</script>

作者：itmyhome