lintcode-easy-Compare Strings
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Compare two strings A and B, determine whether A contains all of the characters in B.
The characters in string A and B are all Upper Case letters.
Example
For A = "ABCD"
, B = "ACD"
, return true
.
For A = "ABCD"
, B = "AABC"
, return false
.
Note
The characters of B in A are not necessary continuous or ordered.
这道题也没太多好说的,cracking code interview提过这种小技巧
public class Solution { /** * @param A : A string includes Upper Case letters * @param B : A string includes Upper Case letter * @return : if string A contains all of the characters in B return true else return false */ public boolean compareStrings(String A, String B) { // write your code here if(A == null) return false; if(B == null || B.length() == 0) return true; int[] count = new int[26]; int lengthA = A.length(); int lengthB = B.length(); if(lengthB > lengthA) return false; for(int i = 0; i < lengthA; i++){ count[A.charAt(i) - ‘A‘]++; } for(int i = 0; i < lengthB; i++){ count[B.charAt(i) - ‘A‘]--; if(count[B.charAt(i) - ‘A‘] < 0) return false; } return true; } }
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