BJFU 1057

Posted 2020-08-21

描述

 

斐波那契额数列，我们都知道。现在qingyezhu想求斐波那契的某项值对2的某次方的结果。你可以帮一下他吗？他好可怜哦！计算了N的N次方次都错了，也挨了ben大哥的N的N次方次的训了。我想你是个好孩子，该会帮他一下吧。不会浪费你多久的时间的。如下是斐波那契数列的定义：

F[0]=1,F[1]=1,F[i]=F[i-1]+F[i-2],其中i>=2.

 

输入

输入有多组。每一组两个非负数M(0<=M<32)和N(0<=N<92)，之间用空格隔开，且每一组数据占一行。

输出

对每组输入数据，请输出F[N]对2^M的求余的结果，每组结果占一行！

样例输入

2 2
2 3
5 28

样例输出

2
3
21

也是被网上不良小工具给坑了，斐波那契的表最后十几个值全都不对，一直WA了二十几次，后来自己写了个斐波那契的函数打出来的数才AC了↓

 1 #include <iostream>
 2 using namespace std;
 3 int main()
 4 {
 5     long long n,m;
 6     while(cin>>m>>n)
 7     {
 8         long long fib[] = {1,1,2,3,5,8,13,21,34,55,89,144,233,
 9                            377,610,987,1597,2584,4181,6765,10946 ,17711, 28657,
10                            46368, 75025, 121393, 196418, 317811 ,514229 ,832040 ,1346269 ,
11                            2178309LL ,3524578LL ,5702887LL ,9227465LL ,14930352LL ,24157817LL ,
12                            39088169LL ,63245986LL ,102334155LL ,165580141LL ,267914296LL ,433494437LL,
13                            701408733LL ,1134903170LL ,1836311903LL ,2971215073LL ,4807526976LL,
14                            7778742049LL ,12586269025LL ,20365011074LL ,32951280099LL ,53316291173LL,
15                            86267571272LL ,139583862445LL ,225851433717LL ,365435296162LL ,
16                            591286729879LL ,956722026041LL ,1548008755920LL ,2504730781961LL,
17                            4052739537881LL ,6557470319842LL ,10610209857723LL ,17167680177565LL,
18                            27777890035288LL ,44945570212853LL ,72723460248141LL ,117669030460994LL,
19                            190392490709135LL ,308061521170129LL ,498454011879264LL,
20                            806515533049393LL ,1304969544928657LL ,2111485077978050LL,
21                            3416454622906707LL ,5527939700884757LL ,8944394323791464LL ,
22                            14472334024676221LL ,23416728348467685LL ,37889062373143906LL ,
23                            61305790721611591LL ,99194853094755497LL ,160500643816367088LL ,
24                            259695496911122585LL ,420196140727489673LL ,679891637638612258LL ,
25                            1100087778366101931LL ,1779979416004714189LL ,2880067194370816120LL ,
26                            4660046610375530309LL,7540113804746346429LL
27                           };
28         long long twow[]=
29         {
30             1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384,32768LL,65536LL,
31             131072LL,262144LL,524288LL,1048576LL,2097152LL,4194304LL,8388608LL,16777216LL,33554432LL,
32             67108864LL,134217728LL,268435456LL,536870912LL,1073741824LL,2147483648LL
33         };
34         cout<<(fib[n]&(twow[m]-1))<<endl;
35     }
36     return 0;
37 }