列表按相同元素分割

Posted 2020-08-21 青禹小生

如将列表[0,0,0,1,1,2,3,3,3,2,3,3,0,0]分割成[0,0,0],[1,1],[2],[3,3,3],[2],[3,3],[0,0]
思路：取出相同元素的索引，根据索引再去对列表进行切片

def split_by_item(num_list):
    temp = []
    split_list=[]
    for i in range(len(num_list)):
        if i < len(num_list)-1:
            if num_list[i] != num_list[i+1]:
                temp.append(i+1)
    temp.append(len(num_list))
    for j in range(len(temp)):
        if j == 0:
            split_list.append(num_list[:temp[j]])
        else:
            split_list.append(num_list[temp[j-1]:temp[j]])
    return split_list