Swift反射机制实现 AppDelegate 字符串获取类并成为根控制器

Posted 2020-08-20 三更小新

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    
        
        window = UIWindow(frame: UIScreen.main.bounds)
        
        // 依据String名字拿到控制器(添加项目名称，命名空间，不能有数字和特殊符号)
        // 返回的是AnyClass？ 需要as？强转
        // 控制器添加Type类型
        let rootControl = NSClassFromString("SwiftyDemo.ViewController") as? UIViewController.Type
        
        let vc = rootControl?.init()
        
        window?.rootViewController = vc
        
        window?.makeKeyAndVisible()
         
        return true
    }

 　　同时可以用info.plist获取命名空间

    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    
        window = UIWindow(frame: UIScreen.main.bounds)
        
        // 依据String名字拿到控制器(添加项目名称，命名空间，不能有数字和特殊符号)
        // 返回的是AnyClass？ 需要as？强转
        // 控制器添加Type类型
//        let rootControl = NSClassFromString("SwiftyDemo.ViewController") as? UIViewController.Type
        
        // 获取命名空间的值，可选
        let str = Bundle.main.infoDictionary?["CFBundleName"] as? String ?? ""
        
        let con = NSClassFromString(str + "." + "ViewController") as? UIViewController.Type
        
        let vc = con?.init()
        
        window?.rootViewController = vc
        
        window?.makeKeyAndVisible()
         
        return true
    }