HDU 4464 Browsing History（最大ASCII的和）

Posted 2020-06-14

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=4464

Problem Description

One day when you are going to clear all your browsing history, you come up with an idea: You want to figure out what your most valued site is. Every site is given a value which equals to the sum of ASCII values of all characters in the URL. For example aa.cc has value of 438 because 438 = 97 + 97 + 46 + 99 + 99. You just need to print the largest value amongst all values of sites.
Things are simplified because you found that all entries in your browsing history are of the following format: [domain], where [domain] consists of lower-case Latin letters and “.” only. See the sample input for more details.

 

Input

There are several test cases.
For each test case, the first line contains an integer n (1 ≤ n ≤ 100), the number of entries in your browsing history.
Then follows n lines, each consisting of one URL whose length will not exceed 100.
Input is terminated by EOF.

 

Output

For each test case, output one line “Case X: Y” where X is the test case number (starting from 1) and Y is a number indicating the desired answer.

 

Sample Input

1
aa.cc
2
www.google.com
www.wikipedia.org

 

Sample Output

Case 1: 438
Case 2: 1728

 

Source

php?

field=problem&key=2012+Asia+Chengdu+Regional+Contest+&source=1&searchmode=source" style="color:rgb(26,92,200); text-decoration:none">2012 Asia Chengdu Regional Contest

题意：

求最大的ASCII的和！

代码例如以下：

#include <cstdio>
#include <cstring>
int main()
{
    int cas = 0;
    int n;
    char s[117];
    while(~scanf("%d",&n))
    {
        getchar();
        int maxx = 0;
        int sum = 0;
        for(int i = 0; i < n; i++)
        {
            gets(s);
            sum = 0;
            int len = strlen(s);
            for(int j = 0; j < len; j++)
            {
                sum += s[j];
            }
            if(sum > maxx)
                maxx = sum;
        }
        printf("Case %d: %d\n",++cas,maxx);
    }
    return 0;
}