132-pattern(蛮难的)
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https://leetcode.com/problems/132-pattern/
下面是我的做法。后来又看了一个提示:
里面的解法非常好。先从后向前找到中间那个数。利用了栈的特性,非常好。
package com.company; import java.util.*; class Solution { public boolean find132pattern(int[] nums) { List<Integer> start = new ArrayList(); List<Integer> end = new ArrayList(); int small = Integer.MAX_VALUE; int big = Integer.MIN_VALUE; for (int i=1; i<nums.length; i++) { if (nums[i] == nums[i-1]) { continue; } if (nums[i] > nums[i-1]) { if (nums[i] > big) { big = nums[i]; } if (nums[i-1] < small) { small = nums[i-1]; } for (int k=0; k<start.size(); k++) { if (nums[i] > start.get(k) && nums[i] < end.get(k)) { return true; } } } else { if (nums[i] > small) { return true; } for (int k=0; k<start.size(); k++) { if (nums[i] > start.get(k) && nums[i] < end.get(k)) { return true; } } if (big > Integer.MIN_VALUE) { start.add(small); end.add(big); //System.out.printf("start: %d, end: %d\n", small, big); small = Integer.MAX_VALUE; big = Integer.MIN_VALUE; } } } return false; } } public class Main { public static void main(String[] args) throws InterruptedException { System.out.println("Hello!"); Solution solution = new Solution(); // Your Codec object will be instantiated and called as such: int[] g = {3, 5, 0, 3, 4}; boolean ret = solution.find132pattern(g); System.out.printf("ret:%b\n", ret); System.out.println(); } }
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