BestCoder Round #73 (div.2)
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1001 Rikka with Chess
ans = n / 2 + m / 2
1002 Rikka with Graph
题意:n + 1条边,问减去至少一条使剩下的图连通的方案数。
分析:原来暴力选一条或两条就行了,脑子笨了。判连通用BFS或并查集,此题并查集更好
#include <cstdio> #include <cmath> #include <cstring> #include <algorithm> #include <vector> #include <map> #include <string> #include <set> using namespace std; typedef long long ll; const int N = 1e2 + 5; struct DSU { int rt[N]; DSU() { memset (rt, -1, sizeof (rt)); } int Find(int x) { return rt[x] == -1 ? x : rt[x] = Find (rt[x]); } void Union(int x, int y) { x = Find (x); y = Find (y); if (x == y) return ; rt[x] = y; } bool same(int x, int y) { return Find (x) == Find (y); } }; int u[N], v[N]; int main(void) { int T; scanf ("%d", &T); while (T--) { int n; scanf ("%d", &n); for (int i=0; i<n+1; ++i) { scanf ("%d%d", u+i, v+i); } int ans = 0; for (int i=0; i<n+1; ++i) { DSU dsu; int edge = 0; for (int j=0; j<n+1; ++j) { if (i == j) continue; if (!dsu.same (u[j], v[j])) { dsu.Union (u[j], v[j]); edge++; } if (edge == n - 1) break; } if (edge == n - 1) ans++; } for (int i=0; i<n+1; ++i) { for (int j=i+1; j<n+1; ++j) { DSU dsu; int edge = 0; for (int k=0; k<n+1; ++k) { if (k == i || k == j) continue; if (!dsu.same (u[k], v[k])) { dsu.Union (u[k], v[k]); edge++; } if (edge == n - 1) break; } if (edge == n - 1) ans++; } } printf ("%d\n", ans); } return 0; }
1003 Rikka with Array
待补
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