QuickHit项目实例

Posted 2020-08-15

关于java面向对象QuickHit项目实例

Game类：用来得到随机出现的字符串（随机打印的字符串，然后玩家进行输入字符串）

public class Game {
	private String sbString;
	Random random = new Random();

	public String player(int level) {
		sbString="";
		for (int i = 0; i < level+1; i++) {
			int rand = random.nextInt(level+1);
			switch (rand) {
			case 0:
				sbString += "1";
				break;
			case 1:
				sbString += "2";
				break;
			case 2:
				sbString += "3";
				break;
			case 3:
				sbString += "4";
				break;
			case 4:
				sbString += "5";
				break;
			case 5:
				sbString += "6";
				break;

			default:
				break;
			}
		}
		return sbString;
	}
}

Level类：进行判断是否输入正确，进行判断时间以及判断级别

public class Level {
	Game game = new Game();
	Scanner san = new Scanner(System.in);
	Date dt1 = new Date();
	Date dt2;
	int num = 0;
	int level = 1;

	public void level() {
		do {
			dt2 = new Date();
			if (level==6) {
				System.out.println("已通过！！！");
				break;
			}
			if (num == 4) {
				num = 0;
				level++;
			}
			if (dt1.getSeconds() > dt2.getSeconds()) {
				if (dt1.getSeconds() - dt2.getSeconds() > 30) {
					System.out.println("超时！！！");
					break;
				} else {
					String sbString = game.player(level);
					System.out.println(sbString);
					String newString = san.next();
					if (newString .equals(sbString) ) {
						System.out.println("输入正确");
						num++;
					} else {
						System.out.println("输出错误");
						break;
					}
				}
			} else if (dt1.getSeconds() < dt2.getSeconds()) {
				if (dt2.getSeconds() - dt1.getSeconds() > 30) {
					System.out.println("超时！！！");
					break;
				} else {
					String sbString = game.player(level);
					System.out.println(sbString);
					String newString = san.next();
					if (newString.equals(sbString)) {
						System.out.println("输入正确");
						num++;
					} else {
						System.out.println("输出错误");
						break;
					}
				}
			}
		} while (true);

	}
}

Test：测试类（main方法）进行运行代码

public class Test {

	public static void main(String[] args) {
		Level level=new Level();
		level.level();
	}
}