Flip Game

Posted amazingzoe

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Flip Game相关的知识,希望对你有一定的参考价值。

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = "++++", after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

 

If there is no valid move, return an empty list [].

 

 1 class Solution {
 2 public:
 3     vector<string> generatePossibleNextMoves(string s) {
 4         vector<string> result;
 5         if (s.size() < 2) return result;
 6         
 7         for (int i = 1; i < s.size(); i++) {
 8             if (s[i] == + && s[i - 1] == +) {
 9                 s[i] = s[i - 1] = -;
10                 result.push_back(s);
11                 s[i] = s[i - 1] = +;
12             } 
13         }
14         return result;
15     }
16 };

 

以上是关于Flip Game的主要内容,如果未能解决你的问题,请参考以下文章

14:Flip Game

POJ_1753——Flip Game(枚举)

LeetCode Flip Game II

POJ1753Flip Game(DFS + 枚举)

LeetCode–Flip Game

Flip Game