UVALive - 3942 Remember the Word[树状数组]

Posted 2020-08-14 Candy?

UVALive - 3942 Remember the Word

A potentiometer, or potmeter for short, is an electronic device with a variable electric resistance. It has two terminals and some kind of control mechanism (often a dial, a wheel or a slide) with which the resistance between the terminals can be adjusted from zero (no resistance) to some maximum value. Resistance is measured in Ohms, and when two or more resistors are connected in series (one after the other, in a row), the total resistance of the array is the sum of the resistances of the individual resistors.

In this problem we will consider an array of N potmeters, numbered 1 to N from left to right. The left terminal of some potmeter numbered x is connected to the right terminal of potmeter x − 1, and its right terminal to the left terminal of potmeter x + 1. The left terminal of potmeter 1 and the right terminal of potmeter N are not connected.

Initially all the potmeters are set to some value between 0 and 1000 Ohms. Then we can do two things:

• Set one of the potmeters to another value.
• Measure the resistance between two terminals anywhere in the array.

Input

The input consists less than 3 cases. Each case starts with N, the number of potmeters in the array, on a line by itself. N can be as large as 200000. Each of next N lines contains one numbers between 0 and 1000, the initial resistances of the potmeters in the order 1 to N. Then follow a number of actions, each on a line by itself. The number of actions can be as many as 200000. There are three types of action:

• “S x r” - set potmeter x to r Ohms. x is a valid potmeter number and r is between 0 and 1000.

• “M x y” - measure the resistance between the left terminal of potmeter x and the right terminal

  of potmeter y. Both numbers will be valid and x is smaller than or equal to y.

• “END” - end of this case. Appears only once at the end of a list of actions.

  A case with N = 0 signals the end of the input and it should not be processed. Output

  For each case in the input produce a line ‘Case n:’, where n is the case number, starting from 1.
  For each measurement in the input, output a line containing one number: the measured resistance

  in Ohms. The actions should be applied to the array of potmeters in the order given in the input. Print a blank line between cases.

  Warning: Input Data is pretty big (∼ 8 MB) so use faster IO. Sample Input

  3
  100
  100
  100 M11 M13
  S 2 200 M12 S30 M23 END
  10
  1
  2
  3
  4
  5
  6
  7
  8
  9
  10
  M 1 10 END
  0

  Sample Output

  Case 1:
  100
  300
  300
  

  200

  Case 2: 55 

---

单点修改和区间查询

 

改成y等价于+y-a[x]

 

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <map>
using namespace std;
const int N=2e5+5;
inline int read(){
    char c=getchar();int x=0,f=1;
    while(c<‘0‘||c>‘9‘){if(c==‘-‘)f=-1;c=getchar();}
    while(c>=‘0‘&&c<=‘9‘){x=x*10+c-‘0‘;c=getchar();}
    return x*f;
}
int n,a[N],c[N],x,y;
char op[10];
inline int lowbit(int x){return x&-x;}
inline void build(int n){
    memset(c,0,sizeof(c));
    for(int i=1;i<=n;i++){
        c[i]+=a[i];
        if(i+lowbit(i)<=n) c[i+lowbit(i)]+=c[i];
    }
}
inline void add(int p,int v){
    a[p]+=v;
    for(int i=p;i<=n;i+=lowbit(i)) c[i]+=v; 
}
inline int sum(int p){
    int ans=0;
    for(int i=p;i>0;i-=lowbit(i)) ans+=c[i];
    return ans;
}
int main(){
    int cas=0;
    while((n=read())){
        if(cas!=0) putchar(‘\n‘);
        printf("Case %d:\n",++cas);
        for(int i=1;i<=n;i++) a[i]=read();
        build(n);
        while(true){
            scanf("%s",op);
            if(op[0]==‘E‘) break;
            if(op[0]==‘S‘){
                x=read();y=read();
                y=y-a[x];
                add(x,y);
            }else{
                x=read();y=read();
                printf("%d\n",sum(y)-sum(x-1));
            }
        }
    }
}