XDOJ_1002_dp

Posted 2020-08-14

http://acm.xidian.edu.cn/problem.php?id=1002

 

dp[i][j][k] 代表i长，j个绿，k个蓝造成的最大伤害。

 

#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#define LL long long
using namespace std;

LL n,x,y,z,t;
LL dp[105][105][105];

int main()
{
    while(~scanf("%d",&n))
    {
        scanf("%lld%lld%lld%lld",&x,&y,&z,&t);
        memset(dp,0,sizeof(dp));
        dp[1][0][0] = x*t;
        for(int i = 2;i <= n;i++)
        {
            for(int g = 0;g <= i;g++)
            {
                int b = 0;
                for(b = 0;b+g < i;b++)
                {
                    int r = i-g-b;
                    dp[i][g][b] = dp[i-1][g][b]+(g*y+x)*(b*z+t);
                }
                if(g > 0)    dp[i][g][b] = max(dp[i][g][b],dp[i-1][g-1][b]+y*(g-1)*(b*z+t));
                if(b > 0)    dp[i][g][b] = max(dp[i][g][b],dp[i-1][g][b-1]+g*y*((b-1)*z+t));
            }
        }
        LL ans = 0;
        printf("%lld\n",dp[2][1][1]);
        for(int i = 0;i <= n;i++)
        {
            for(int j = 0;j+i <= n;j++)    ans = max(ans,dp[n][i][j]);
        }
        printf("%lld\n",ans);
    }    
    return 0;
}