栈的题目

Posted 2020-08-14 小困

栈的特点，就是先进后出。栈可以是链表形式，也可以用数组形式实现。

package 程序员面试金典;

/**
 * 第三章
 */
public class Unit3 {

    public static void main(String[] args) {
        
    }

}

// 第一题 一个数组三个栈，返回最小值O(1)
class stackMyself {
    private int[] data = new int[30];
    private int stack1 = 0;
    private int stack2 = 10;
    private int stack3 = 20;
    private int minStack1 = 0;

    public stackMyself() {

    }

    // 栈1--
    public int getMin() {
        return minStack1;
    }

    public void pushStack1(int d) {
        if (stack1 < 10) {
            if (stack1 == 0)
                minStack1 = d;
            else {
                if (d < minStack1)
                    minStack1 = d;
            }
            data[stack1++] = d;
        } else {
            System.err.println("栈1满了");
        }
    }

    public int popStack1() {
        if (stack1 >= 0)
            return data[--stack1];
        else
            return -1;
    }

    public int getStack1Top() {
        int t = stack1 - 1;
        return data[t];
    }

    // 栈2
    public void pushStack2(int d) {
        if (stack2 < 20)
            data[stack2++] = d;
        else {
            System.err.println("栈2满了");
        }
    }

    public int popStack2() {
        if (stack2 >= 10)
            return data[--stack2];
        else
            return -1;
    }

    public int getStack2Top() {
        int t = stack2 - 1;
        return data[t];
    }

    // 栈3
    public void pushStack3(int d) {
        if (stack3 < 30)
            data[stack3++] = d;
        else {
            System.err.println("栈3满了");
        }
    }

    public int popStack3() {
        if (stack3 >= 20)
            return data[--stack3];
        else
            return -1;
    }

    public int getStack3Top() {
        int t = stack3 - 1;
        return data[t];
    }

}

// 链式栈
class SetOfStack {
    private stackNode first;
    private stackNode current;

    public SetOfStack() {
        first = new stackNode();
        first.setNext(null);
        current = first;
    }

    // 入栈
    public void insertValue(int d) {
        stackNode runner = first;
        while (runner.getNext() != null)
            runner = runner.getNext();
        if (runner.getTop() != runner.getSize() - 1)
            runner.push(d);
        else {
            stackNode newnode = new stackNode();
            runner.setNext(newnode);
            runner = newnode;
            runner.push(d);
            current = runner;
        }
    }

    // 出栈
    public int pop() {
        if (current.getTop() == -1) {
            stackNode runner = first;
            while (runner.getNext() != current)
                runner = runner.getNext();
            current = runner;
            current.setNext(null);
        }
        return current.pop();
    }

    // 打印
    public void printStack() {
        stackNode runner = first;
        while (runner != null) {
            runner.printStack();
            runner = runner.getNext();
        }
    }
}

class stackNode {
    private stackNode next;
    private int[] data;
    private int size = 10;
    private int top = -1;

    public stackNode() {
        data = new int[size];
    }

    public stackNode getNext() {
        return next;
    }

    public int getTop() {
        return top;
    }

    public int getSize() {
        return size;
    }

    public void setNext(stackNode next) {
        this.next = next;
    }

    // 入栈
    public void push(int d) {
        if (top != size - 1)
            data[++top] = d;
        else
            System.err.println("此栈已满");
    }

    // 出栈
    public int pop() {
        if (top != -1)
            return data[top--];
        else
            return -1;
    }

    // 打印栈
    public void printStack() {
        for (int i = 0; i <= top; i++)
            System.out.print(data[i] + " ");
        System.out.println();
    }
}

// 汉诺塔栈
class haniostack {
    private stackNode Astack;
    private stackNode Bstack;
    private stackNode Cstack;

    public hanioStack() {
        Astack = new stackNode();
        Bstack = new stackNode();
        Cstack = new stackNode();
    }

    public void initA(int[] data) {
        for (int i = 0; i < data.length; i++)
            Astack.push(data[i]);
    }

    public void MoveTo(char A, char C) {
        if (A == \'A\' && C == \'C\') {
            int data = Astack.pop();
            Cstack.push(data);
        } else if (A == \'A\' && C == \'B\') {
            int data = Astack.pop();
            Bstack.push(data);
        } else if (A == \'B\' && C == \'C\') {
            int data = Bstack.pop();
            Cstack.push(data);
        } else if (A == \'B\' && C == \'A\') {
            int data = Bstack.pop();
            Astack.push(data);
        } else if (A == \'C\' && C == \'A\') {
            int data = Cstack.pop();
            Astack.push(data);
        } else if (A == \'C\' && C == \'B\') {
            int data = Cstack.pop();
            Bstack.push(data);
        }
        printStack();
    }

    public void HanioTower(int n, char A, char B, char C) {
        
        if (n == 1)
            MoveTo(A, C);
        else {
            HanioTower(n - 1, A, C, B);
            MoveTo(A, C);
            HanioTower(n - 1, B, A, C);
        }

    }

    public void printStack() {
        System.out.print("A:");
        Astack.printStack();
        System.out.print("B:");
        Bstack.printStack();
        System.out.print("C:");
        Cstack.printStack();
    }
}
class MyQueue{
    private stackNode stack1;
    private stackNode stack2;
    public void inQueue(int data){
        while(stack2.getTop() != -1)
        {
            int d = stack2.pop();
            stack1.push(d);
        }
        stack1.push(data);
    }
    public int outQueue(){
        while(stack1.getTop() != -1)
        {
            int d = stack1.pop();
            stack2.push(d);
        }
        return stack1.pop();
    }
}

 思考题目的时候，已形成本能，不知道如何总结。反过来想的话，就是问题和数据结构的特性。比如第一题，一个数组三个栈，那么肯定是分割数组了。比如MyQueue这题，因为栈是先进后出，队列是先进先出。题目要求可以用两个栈，那么肯定是可以来回倒腾，把最先和最后元素呈现出来。栈的特性，和一些经典问题切合可以更深理解数据结构。比如表达式的变换（前缀，中缀，后缀），以及树遍历的非递归法，等等。比如代码中函数的调用，递归也是将顶层函数压栈，到底了之后不断弹出执行。