1799恐怖袭击
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题意:给定一个无向图,n个顶点(1 <= n < 1000),m条带权边(1 <= m < 1000000),权值为d(1 <= d < 100),现给定 s个起始点和t个终点(1 <= s, t < 10),求任意一个起点到任意一个终点的最短路程。
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<string> 5 #include<sstream> 6 #include<algorithm> 7 #include<cmath> 8 #include<set> 9 #include<map> 10 #include<stack> 11 #include<queue> 12 #include<deque> 13 #include<cstdlib> 14 #include<cctype> 15 #include<list> 16 #include<vector> 17 using namespace std; 18 const int INF = 0x7f7f7f7f; 19 const int MAXN = 1000 + 10; 20 struct Edge 21 { 22 int from_, to_, dist_; 23 Edge(int from = 0, int to = 0, int dist= 0):from_(from), to_(to), dist_(dist){} 24 }; 25 struct HeapNode 26 { 27 int d_, u_; 28 HeapNode(int d, int u):d_(d), u_(u){} 29 bool operator < (const HeapNode& rhs) const 30 { 31 return d_ > rhs.d_; 32 } 33 }; 34 struct Dijkstra 35 { 36 int n, m; 37 vector<Edge> edges; 38 vector<int> G[MAXN]; 39 bool done[MAXN]; 40 int d[MAXN]; 41 int p[MAXN]; 42 void init(int n) 43 { 44 this -> n = n; 45 for(int i = 0; i < n; ++i) 46 G[i].clear(); 47 edges.clear(); 48 } 49 void AddEdge(int from, int to, int dist) 50 { 51 edges.push_back(Edge(from, to, dist)); 52 m = edges.size(); 53 G[from].push_back(m - 1); 54 } 55 void dijkstra(int s) 56 { 57 priority_queue<HeapNode> Q; 58 for(int i = 0; i < n; ++i) 59 d[i] = INF; 60 d[s] = 0; 61 memset(done, 0, sizeof done); 62 Q.push(HeapNode(0, s)); 63 while(!Q.empty()) 64 { 65 HeapNode x = Q.top(); 66 Q.pop(); 67 int u = x.u_; 68 if(done[u]) continue; 69 done[u] = true; 70 for(int i = 0; i < G[u].size(); ++i) 71 { 72 Edge& e = edges[G[u][i]]; 73 if(d[e.to_] > d[u] + e.dist_) 74 { 75 d[e.to_] = d[u] + e.dist_; 76 p[e.to_] = G[u][i]; 77 Q.push(HeapNode(d[e.to_], e.to_)); 78 } 79 } 80 81 } 82 } 83 }; 84 int a[15]; 85 int b[15]; 86 int main() 87 { 88 int n, m, s, t; 89 while(scanf("%d%d%d%d", &n, &m, &s, &t) == 4) 90 { 91 if(!n && !m && !s && !t) return 0; 92 memset(a, 0, sizeof a); 93 memset(b, 0, sizeof b); 94 Dijkstra dij; 95 dij.init(n); 96 while(m--) 97 { 98 int u, v, d; 99 scanf("%d%d%d", &u, &v, &d); 100 dij.AddEdge(u - 1, v - 1, d); 101 dij.AddEdge(v - 1, u - 1, d); 102 } 103 for(int i = 0; i < s; ++i) 104 scanf("%d", &a[i]); 105 for(int i = 0; i < t; ++i) 106 scanf("%d", &b[i]); 107 int ans = INF; 108 for(int i = 0; i < s; ++i) 109 { 110 dij.dijkstra(a[i] - 1); 111 for(int j = 0; j < t; ++j) 112 ans = min(ans, dij.d[b[j] - 1]); 113 } 114 if(ans == INF) 115 printf("What a pity!\n"); 116 else printf("%d\n", ans); 117 } 118 return 0; 119 }
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