HDU_1394_线段数

Posted 2020-08-12 冷暖知不知

http://acm.hdu.edu.cn/showproblem.php?pid=1394

 

线段数入门题，每次读入一个数，就寻找在树中比它大的值的个数，然后跟新数，把个数相加就是逆序数，每移动一个数，相当于当前逆序数加上比首元素大的数的数量，减去比首元素小的数的数量。

 

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

struct segtree
{
    int left,right,sum;
}tree[10050];
int n,a[5050];

void build(int pos,int l,int r)
{
    tree[pos].left = l;
    tree[pos].right = r;
    tree[pos].sum = 0;
    if(l < r)
    {
        int mid = (l+r)/2;
        build(pos*2,l,mid);
        build(pos*2+1,mid+1,r);
    }
}

int getsum(int pos,int l,int r)
{
    if(tree[pos].left == l && tree[pos].right == r)   return tree[pos].sum;
    int mid = (tree[pos].left+tree[pos].right)/2;
    if(r <= mid)    return getsum(pos*2,l,r);
    if(l > mid)     return getsum(pos*2+1,l,r);
    return getsum(pos*2,l,mid)+getsum(pos*2+1,mid+1,r);
}

void update(int pos,int num)
{
    tree[pos].sum++;
    if(tree[pos].left == tree[pos].right)   return;
    int mid = (tree[pos].left+tree[pos].right)/2;
    if(num <= mid)  update(pos*2,num);
    else    update(pos*2+1,num);
}

int main()
{
    while(~scanf("%d",&n))
    {
        int ans = 0;
        build(1,0,n-1);
        for(int i = 0;i < n;i++)
        {
            scanf("%d",&a[i]);
            ans += getsum(1,a[i],n-1);
            update(1,a[i]);
        }
        int temp = ans;
        for(int i = 0;i < n-1;i++)
        {
            temp += n-1-a[i]-a[i];
            ans = min(temp,ans);
        }
        printf("%d\n",ans);
    }
    return 0;
}