元祖方法

Posted 2020-08-11

PS：元祖和列表几乎一样

       但是列表可以进行修改，元祖不能进行修改

1.元祖

  name_tuple = ("cos", "sin", "tan")

  # 索引
  print (name_tuple[0])
  # len
  print (name_tuple[len(name_tuple)-1])
  # 分片
  print (name_tuple[0:1])
  # for 循环
  for n in name_tuple:
  print (n)
  # 删除不支持
  del name_tuple[1]  ps:元祖不能进行修改的

 

2.count 计算元素出现的个数

  name_tuple = ("cos", "sin", "tan", "sin")
  print (name_tuple.count("sin"))

 

3.index 获取指定元素的索引位置

  name_tuple = ("cos", "sin", "tan")
  print (name_tuple.index("sin"))