Range Sum Query - Mutable
Posted Sheryl Wang
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Range Sum Query - Mutable相关的知识,希望对你有一定的参考价值。
class SegmentTreeNode(object): def __init__(self, start, end): self.start = start self.end = end self.sum = 0 self.left = None self.right = None class NumArray(object): def __init__(self, nums): """ initialize your data structure here. :type nums: List[int] """ n = len(nums) self.root = self.buildTree(nums, 0, n-1) def update(self, i, val): """ :type i: int :type val: int :rtype: int """ self.modifyTree(i,val, self.root) def sumRange(self, i, j): """ sum of elements nums[i..j], inclusive. :type i: int :type j: int :rtype: int """ return self.queryTree(i, j, self.root) def buildTree(self, nums, start, end): if start > end: return None#not valid root = SegmentTreeNode(start, end) if start == end: root.sum = nums[start] return root mid = start + (end - start)/2 root.left = self.buildTree(nums, start, mid) root.right = self.buildTree(nums, mid+1, end) root.sum = root.left.sum + root.right.sum return root def modifyTree(self, i, val, root): if not root: return 0 if root.start==i and root.end == i: diff = val - root.sum root.sum = val return diff mid = (root.start + root.end)/2 if i > mid: diff = self.modifyTree(i, val, root.right) else: diff = self.modifyTree(i, val, root.left) root.sum = root.sum + diff return diff def queryTree(self, i, j, root): if not root: return 0 if root.start == i and root.end == j: return root.sum mid = (root.start + root.end)/2 if i > mid: return self.queryTree(i, j, root.right) if j <= mid: return self.queryTree(i, j, root.left) return self.queryTree(i, mid, root.left)+self.queryTree(mid+1, j , root.right) # Your NumArray object will be instantiated and called as such: # numArray = NumArray(nums) # numArray.sumRange(0, 1) # numArray.update(1, 10) # numArray.sumRange(1, 2)
以上是关于Range Sum Query - Mutable的主要内容,如果未能解决你的问题,请参考以下文章
307. Range Sum Query - Mutable