76. Minimum Window Substring
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Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).
For example,
S = "ADOBECODEBANC"
T = "ABC"
Minimum window is "BANC"
.
Note:
If there is no such window in S that covers all characters in T, return the empty string ""
.
If there are multiple such windows, you are guaranteed that there will always be only one unique minimum window in S.
public string MinWindow(string s, string t) { if(t==null || t == "" || s == "") return t; if(t.Length > s.Length) return ""; int max =s.Length+1; var res =""; var hashtable = new Dictionary<char,int>(); int min =s.Length; for(int i =0;i< t.Length;i++) { if(hashtable.ContainsKey(t[i])) hashtable[t[i]]++; else hashtable.Add(t[i],1); } for(int i = 0;i<=s.Length - t.Length;i++) { var exist = new Dictionary<char,int>(); int count =0; for(int j = i;j<s.Length;j++) { if(max < j-i+1) break; if(hashtable.ContainsKey(s[j])) { if(exist.ContainsKey(s[j])) { if(exist[s[j]] < hashtable[s[j]]) { count++; exist[s[j]]++; if(count >= t.Length) { if(max > j-i+1) {res =s.Substring(i,j-i+1);max = j-i+1;} break; } } } else { count++; exist.Add(s[j],1); if(count >= t.Length) { if(max > j-i+1) {res =s.Substring(i,j-i+1);max = j-i+1;} break; } } } } } return res; }
public string MinWindow(string s, string t) { if(t==null || t == "" ||s==mull|| s == "") return t; if(t.Length > s.Length) return ""; int max =s.Length+1; var res =""; var hashtable = new Dictionary<char,int>(); for(int i =0;i< t.Length;i++) { if(hashtable.ContainsKey(t[i])) hashtable[t[i]]++; else hashtable.Add(t[i],1); } int left =0; int right =-1; int count = 0; while(right<s.Length) { if(count == t.Length) { if(max > right - left + 1) { max= right - left + 1; res = s.Substring(left,right - left + 1); } if(hashtable.ContainsKey(s[left])) { if(hashtable[s[left]] ==0) count--; hashtable[s[left]]++; } left++; } else if(right<s.Length-1) { right++; if(hashtable.ContainsKey(s[right]) ) { if(hashtable[s[right]]>0) count++; hashtable[s[right]]--; } } else right++; } return res; }
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