UVa 11040 Add bricks in the wall (水题递推)
Posted dwtfukgv
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了UVa 11040 Add bricks in the wall (水题递推)相关的知识,希望对你有一定的参考价值。
题意:给定一个金字塔,除了最后一行,每个数都等于支撑它的两个数的和,现在给奇数行的左数奇数位置,求整个金字塔。
析:很容易看出来,从下往上奇数行等于 a[i][j] = (a[i-2][j-1] - a[i][j-1] - a[i][j+1]) / 2;然后偶数行就推出来了。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #define print(a) printf("%d\n", (a)) #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const LL LNF = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e3 + 5; const int mod = 1e9 + 7; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline int Min(int a, int b){ return a < b ? a : b; } inline int Max(int a, int b){ return a > b ? a : b; } inline LL Min(LL a, LL b){ return a < b ? a : b; } inline LL Max(LL a, LL b){ return a > b ? a : b; } inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } int a[15][15]; int main(){ cin >> n; while(n--){ memset(a, 0, sizeof(a)); for(int i = 1; i < 10; i += 2) for(int j = 1; j <= i; j += 2) cin >> a[i][j]; for(int i = 1; i < 10; i++) for(int j = 2; j <= i; j++) if(!a[i][j]) a[i][j] = (a[i-2][j-1] - a[i][j-1] - a[i][j+1]) / 2; for(int i = 2; i < 9; i += 2) for(int j = 1; j <= i; j++) a[i][j] = a[i+1][j] + a[i+1][j+1]; for(int i = 1; i < 10; i++) for(int j = 1; j <= i; j++) if(j == i) printf("%d\n", a[i][j]); else printf("%d ", a[i][j]); } return 0; }
以上是关于UVa 11040 Add bricks in the wall (水题递推)的主要内容,如果未能解决你的问题,请参考以下文章