对象原型

Posted 2020-08-09 。。。

如何判断一个对象的方法是来自这个本身的还是原型的？

function Person() {
}
 
Person.prototype.name="Nicholas";
Person.prototype.age=29;
Person.prototype.sayName=function(){
    alert(this.name);
}
 
var person1=new Person();
person1.name="Greg";
 
var person2=new Person();
 
console.log(person1.hasOwnProperty("name"));//true
console.log(person2.hasOwnProperty("name"));//false
 
console.log("name" in person1);//true
console.log("name" in person2);//true
 
for (var prop in person1) {
    console.log(prop);//name   age   sayName
}
 
function hasPrototypeProperty(object,pro) {//如此可判断存在于原型中的属性
    return (!object.hasOwnProperty(pro))&&(pro in object);
}
console.log(hasPrototypeProperty(person1,"name"));//false
console.log(hasPrototypeProperty(person2,"name"));//true

 

function Person() { }   Person.prototype.name="Nicholas"; Person.prototype.age=29; Person.prototype.sayName=function(){     alert(this.name); }   var person1=new Person(); person1.name="Greg";   var person2=new Person();   console.log(person1.hasOwnProperty("name"));//true console.log(person2.hasOwnProperty("name"));//false   console.log("name" in person1);//true console.log("name" in person2);//true   for (var prop in person1) {     console.log(prop);//name   age   sayName }   function hasPrototypeProperty(object,pro) {//如此可判断存在于原型中的属性     return (!object.hasOwnProperty(pro))&&(pro in object); } console.log(hasPrototypeProperty(person1,"name"));//false console.log(hasPrototypeProperty(person2,"name"));//true