python代码学习day03

Posted 2020-06-13

有关列表的处理一例

#!/usr/bin/env python 
#coding:utf8

name = [‘!‘, ‘#‘, ‘*‘, ‘Eric‘, ‘alex‘, ‘jack‘, ‘jack‘, ‘a‘, ‘b‘, ‘c‘, ‘d‘, 1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 6,2332,4,2,6,2]
first_pos = 0

for i in range(name.count(2)):  ##统计出有关2的总数有多少个
new_list = name[first_pos:]     ##将列表赋值
next_pos = new_list.index(2)+1  ##得到获取的2的下一个位置是多少
print "Find postion:",first_pos+new_list.index(2),‘Next:‘,next_pos ##输出
first_pos += next_pos           ## 对pos点进行累加

得到的结果是

Find postion: 12 Next: 13
Find postion: 18 Next: 6
Find postion: 25 Next: 7
Find postion: 27 Next: 2

 

有一个更简单的方法使用index

pos = 0
for i in range(name.count(2)):
    if pos == 0:
        pos = name.index(2)
    else:
        pos = name.index(2,pos+1)
    print pos

结果是

12
18
25
27