SQLAlchemy 一对多

Posted 2020-08-09 godjob

下述範例描述了電影同導演的多對一關係。範例中說明了從用戶定義的Python類建立數據表的方法，雙方關係例項的建立方法，以及最終查詢數據的方法：包括延遲載入和預先載入兩種自動生成的SQL查詢。

結構定義

建立兩個Python類以及DBMS中對應的數據表：

from sqlalchemy import *
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import relation, sessionmaker

Base = declarative_base()
 
class Movie(Base):
    __tablename__ = ‘movies‘
 
    id = Column(Integer, primary_key=True)
    title = Column(String(255), nullable=False)
    year = Column(Integer)
    directed_by = Column(Integer, ForeignKey(‘directors.id‘))
 
    director = relation("Director", backref=‘movies‘, lazy=False)
 
    def __init__(self, title=None, year=None):
        self.title = title
        self.year = year
    def __repr__(self):
        return "Movie(%r, %r, %r)" % (self.title, self.year, self.director)
 
class Director(Base):
    __tablename__ = ‘directors‘
 
    id = Column(Integer, primary_key=True)
    name = Column(String(50), nullable=False, unique=True)
 
    def __init__(self, name=None):
        self.name = name
 
    def __repr__(self):
        return "Director(%r)" % (self.name)
 
engine = create_engine(‘dbms://user:[email protected]/dbname‘)
Base.metadata.create_all(engine)

插入數據

插入的電影和導演物件可以互相參照：

Session = sessionmaker(bind=engine)
session = Session()

m1 = Movie("Star Trek", 2009)
m1.director = Director("JJ Abrams")

d2 = Director("George Lucas")
d2.movies = [Movie("Star Wars", 1977), Movie("THX 1138", 1971)]

try:
    session.add(m1)
    session.add(d2)
    session.commit()
except:
    session.rollback()

查詢

alldata = session.query(Movie).all()
for somedata in alldata:
    print somedata

SQLAlchemy將向DBMS（忽略差異）發起如下查詢：

SELECT movies.id, movies.title, movies.year, movies.directed_by, directors.id, directors.name 
FROM movies LEFT OUTER JOIN directors ON directors.id = movies.directed_by

並輸出：

Movie(‘Star Trek‘, 2009L, Director(‘JJ Abrams‘))
Movie(‘Star Wars‘, 1977L, Director(‘George Lucas‘))
Movie(‘THX 1138‘, 1971L, Director(‘George Lucas‘))

假如設定lazy=True（預設值），SQLAlchemy將首先發起對電影列表的查詢，並在必要時（延遲載入）逐一查詢導演的名稱：

SELECT movies.id, movies.title, movies.year, movies.directed_by 
FROM movies

SELECT directors.id, directors.name
FROM directors 
WHERE directors.id = %s