CodeForces 670E Correct Bracket Sequence Editor
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链表,模拟。
写一个双向链表模拟一下过程。
#pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map> #include<set> #include<queue> #include<stack> #include<iostream> using namespace std; typedef long long LL; const double pi=acos(-1.0),eps=1e-6; void File() { freopen("D:\\in.txt","r",stdin); freopen("D:\\out.txt","w",stdout); } template <class T> inline void read(T &x) { char c=getchar(); x=0; while(!isdigit(c)) c=getchar(); while(isdigit(c)) {x=x*10+c-‘0‘; c=getchar();} } const int maxn=500010; struct X { bool f; int nx,pr; }s[maxn]; char t[maxn],op[maxn]; int n,m,p; stack<int>S; int flag[maxn]; int f1[maxn],f2[maxn]; int main() { scanf("%d%d%d",&n,&m,&p); p--; scanf("%s",t); int len=strlen(t); for(int i=0;t[i];i++) { if(S.empty()) S.push(i); else { if(t[i]==‘(‘) S.push(i); else { if(t[S.top()]==‘(‘) { f1[S.top()]=i, f2[i]=S.top(); S.pop(); } else S.push(i); } } } for(int i=0;i<len;i++) { if(t[i]==‘(‘) s[i].f=0; else s[i].f=1; s[i].pr=s[i].nx=-1; if(i!=0) s[i].pr=i-1; if(i!=len-1) s[i].nx=i+1; } scanf("%s",op); for(int i=0;op[i];i++) { if(op[i]==‘L‘) p=s[p].pr; else if(op[i]==‘R‘) p=s[p].nx; else { int pos1=p,pos2; if(s[p].f==0) pos2=f1[p]; else pos2=f2[p]; if(pos1>pos2) swap(pos1,pos2); // for(int j=pos1;j<=pos2;j++) flag[j]=1; flag[pos1]++; flag[pos2+1]--; if(s[pos1].pr!=-1) s[s[pos1].pr].nx=s[pos2].nx; if(s[pos2].nx!=-1) s[s[pos2].nx].pr=s[pos1].pr; if(s[pos2].nx!=-1) p=s[pos2].nx; else p=s[pos1].pr; } } LL sum=0; // for(int i=0;i<len;i++) printf("%d ",flag[i]); // printf("\n"); for(int i=0;i<len;i++) { sum=sum+flag[i]; if(sum>0) continue; printf("%c",t[i]); } printf("\n"); return 0; }
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