1057. Stack (30)

Posted

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了1057. Stack (30)相关的知识,希望对你有一定的参考价值。

Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element). Now you are supposed to implement a stack with an extra operation: PeekMedian -- return the median value of all the elements in the stack. With N elements, the median value is defined to be the (N/2)-th smallest element if N is even, or ((N+1)/2)-th if N is odd.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<= 105). Then N lines follow, each contains a command in one of the following 3 formats:

Push key
Pop
PeekMedian

where key is a positive integer no more than 105.

Output Specification:

For each Push command, insert key into the stack and output nothing. For each Pop or PeekMedian command, print in a line the corresponding returned value. If the command is invalid, print "Invalid" instead.

Sample Input:

17
Pop
PeekMedian
Push 3
PeekMedian
Push 2
PeekMedian
Push 1
PeekMedian
Pop
Pop
Push 5
Push 4
PeekMedian
Pop
Pop
Pop
Pop

Sample Output:

Invalid
Invalid
3
2
2
1
2
4
4
5
3
Invalid

 

 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<vector>
 4 #include<algorithm>
 5 using namespace std;
 6 int cards[318];
 7 int Hash[100100];
 8 int main()
 9 {
10     int n;
11     scanf("%d",&n);
12     vector<int> vv;
13     for (int i = 0 ;i < n; ++i)
14     {
15         char str[11];
16         int val;
17         scanf("%s",str);
18         if (strcmp(str,"Pop")==0)
19         {
20             if(vv.empty())
21             {
22                 printf("Invalid\n");
23             }
24             else
25             {
26                 printf("%d\n",vv[vv.size()-1]);
27                 int key = vv[vv.size()-1];
28                 vv.pop_back();
29                 int index = key / 318;
30                 --cards[index];
31                 --Hash[key];
32             }
33         }
34         else if (strcmp(str,"Push")==0)
35         {
36             scanf("%d",&val);
37             vv.push_back(val);
38             int index = val / 318;
39             ++cards[index];
40             ++Hash[val];
41         }
42         else if (strcmp(str,"PeekMedian")==0)
43         {
44             if(vv.empty())
45             {
46                 printf("Invalid\n");
47             }
48             else
49             {
50                 int all = (vv.size()+1) / 2 ;
51                 int sum = 0 , index = 0;
52                 while(sum + cards[index] < all)
53                 {
54                     sum += cards[index];
55                     ++ index;
56                 }
57                 int bg = index * 318 - 1;
58                 sum = all - sum;
59                 while(sum > 0)
60                 {
61                     ++ bg;
62                     if(Hash[bg] > 0)
63                     {
64                         sum -= Hash[bg];
65                     }    
66                 }
67                 printf("%d\n",bg);
68             }
69         }
70     }
71     return 0;
72 }

 

以上是关于1057. Stack (30)的主要内容,如果未能解决你的问题,请参考以下文章

PAT 甲级1057 Stack (30 分)(不会,树状数组+二分)*****

1057. Stack (30) - 树状数组

PAT (Advanced Level) 1057. Stack (30)

PAT甲题题解-1057. Stack (30)-树状数组

PAT.1057 Stack(线段树)

PAT.1057 Stack(线段树)