Python怎么return后让循环继续运行？

Posted 2023-02-16

执行到return语句时，会退出函数，return之后的语句不再执行。

但将return语句放在try语句块中，是个例外，finally语句块中的语句依然会执行 。

举例：

正常函数：执行到该return语句时，函数终止，后边的语句不再执行 

def fun(): 

print 98 

return 'ok'

print 98 

try语句中：finally语句块中的语句依然会执行 。

def func(): 

try: 

print 98 

return 'ok' 

finally:

print 98

扩展资料：

return 语句会终止函数的执行，并返回函数的值。 

语法：

return value;

可选项 value指定返回的值。如果忽略则返回undefined。

在函数中 ，return 语句用于终止一个函数的执行，并返回值value。

如果value被省略或在函数内没有 return 语句被执行，则函数返回undefined。 

return语句的用法 ：

1、中止函数的执行，并返回函数执行的结果。

语法为：return+表达式 

return 返回的值可以是任何数据类型 。

2、使用return阻止某些浏览器默认的行为。

语法为：return false;

参考技术A

return 会直接另函数返回，函数就运行结束了，所有该函数体内的代码都不再执行了，所以该函数体内的循环也不可能再继续运行。

如果你需要让循环继续执行，就不能return函数，而应该选用break或者continue。

break：跳出所在的当前整个循环，到外层代码继续执行。

continue：跳出本次循环，从下一个迭代继续运行循环，内层循环执行完毕，外层代码继续运行。

return：直接返回函数，所有该函数体内的代码（包括循环体）都不会再执行。

用下边的示例代码来解释：

def return_continue_break(type):
    if(not type in ["return", "continue", "break"]):
        print '"type" should be "return, continue, break".'
        return
    for j in range(0, 10):
        for i in range(0, 10):
            print "j_i: %d_%d" %(j, i)
            if(i > 3):
               if(type == "return"):
                   return
               elif(type == "continue"):
                   continue
               else:
                   break
            print "executed!"

if __name__ == '__main__':
    return_continue_break("break")
    return_continue_break("continue")
    return_continue_break("return")

BREAK的输出为：

j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4
j_i: 1_0
executed!
j_i: 1_1
executed!
j_i: 1_2
executed!
j_i: 1_3
executed!
j_i: 1_4
j_i: 2_0
executed!
j_i: 2_1
executed!
j_i: 2_2
executed!
j_i: 2_3
executed!
j_i: 2_4
j_i: 3_0
executed!
j_i: 3_1
executed!
j_i: 3_2
executed!
j_i: 3_3
executed!
j_i: 3_4
j_i: 4_0
executed!
j_i: 4_1
executed!
j_i: 4_2
executed!
j_i: 4_3
executed!
j_i: 4_4
j_i: 5_0
executed!
j_i: 5_1
executed!
j_i: 5_2
executed!
j_i: 5_3
executed!
j_i: 5_4
j_i: 6_0
executed!
j_i: 6_1
executed!
j_i: 6_2
executed!
j_i: 6_3
executed!
j_i: 6_4
j_i: 7_0
executed!
j_i: 7_1
executed!
j_i: 7_2
executed!
j_i: 7_3
executed!
j_i: 7_4
j_i: 8_0
executed!
j_i: 8_1
executed!
j_i: 8_2
executed!
j_i: 8_3
executed!
j_i: 8_4
j_i: 9_0
executed!
j_i: 9_1
executed!
j_i: 9_2
executed!
j_i: 9_3
executed!
j_i: 9_4

RETURN的输出为：

j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4

CONTINUE的输出为：

j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4
j_i: 0_5
j_i: 0_6
j_i: 0_7
j_i: 0_8
j_i: 0_9
j_i: 1_0
executed!
j_i: 1_1
executed!
j_i: 1_2
executed!
j_i: 1_3
executed!
j_i: 1_4
j_i: 1_5
j_i: 1_6
j_i: 1_7
j_i: 1_8
j_i: 1_9
j_i: 2_0
executed!
j_i: 2_1
executed!
j_i: 2_2
executed!
j_i: 2_3
executed!
j_i: 2_4
j_i: 2_5
j_i: 2_6
j_i: 2_7
j_i: 2_8
j_i: 2_9
j_i: 3_0
executed!
j_i: 3_1
executed!
j_i: 3_2
executed!
j_i: 3_3
executed!
j_i: 3_4
j_i: 3_5
j_i: 3_6
j_i: 3_7
j_i: 3_8
j_i: 3_9
j_i: 4_0
executed!
j_i: 4_1
executed!
j_i: 4_2
executed!
j_i: 4_3
executed!
j_i: 4_4
j_i: 4_5
j_i: 4_6
j_i: 4_7
j_i: 4_8
j_i: 4_9
j_i: 5_0
executed!
j_i: 5_1
executed!
j_i: 5_2
executed!
j_i: 5_3
executed!
j_i: 5_4
j_i: 5_5
j_i: 5_6
j_i: 5_7
j_i: 5_8
j_i: 5_9
j_i: 6_0
executed!
j_i: 6_1
executed!
j_i: 6_2
executed!
j_i: 6_3
executed!
j_i: 6_4
j_i: 6_5
j_i: 6_6
j_i: 6_7
j_i: 6_8
j_i: 6_9
j_i: 7_0
executed!
j_i: 7_1
executed!
j_i: 7_2
executed!
j_i: 7_3
executed!
j_i: 7_4
j_i: 7_5
j_i: 7_6
j_i: 7_7
j_i: 7_8
j_i: 7_9
j_i: 8_0
executed!
j_i: 8_1
executed!
j_i: 8_2
executed!
j_i: 8_3
executed!
j_i: 8_4
j_i: 8_5
j_i: 8_6
j_i: 8_7
j_i: 8_8
j_i: 8_9
j_i: 9_0
executed!
j_i: 9_1
executed!
j_i: 9_2
executed!
j_i: 9_3
executed!
j_i: 9_4
j_i: 9_5
j_i: 9_6
j_i: 9_7
j_i: 9_8
j_i: 9_9

希望对你有帮助。

参考技术B return 会直接另函数返回，函数就运行结束了，所有该函数体内的代码都不再执行了，所以该函数体内的循环也不可能再继续运行。

如果你需要让循环继续执行，就不能return函数，而应该选用break或者continue。
break：跳出所在的当前整个循环，到外层代码继续执行。
continue：跳出本次循环，从下一个迭代继续运行循环，内层循环执行完毕，外层代码继续运行。
return：直接返回函数，所有该函数体内的代码（包括循环体）都不会再执行。

用下边的示例代码来解释：

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def return_continue_break(type):
if(not type in ["return", "continue", "break"]):
print '"type" should be "return, continue, break".'
return
for j in range(0, 10):
for i in range(0, 10):
print "j_i: %d_%d" %(j, i)
if(i > 3):
if(type == "return"):
return
elif(type == "continue"):
continue
else:
break
print "executed!"

if __name__ == '__main__':
return_continue_break("break")
return_continue_break("continue")
return_continue_break("return")

BREAK的输出为：

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j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4
j_i: 1_0
executed!
j_i: 1_1
executed!
j_i: 1_2
executed!
j_i: 1_3
executed!
j_i: 1_4
j_i: 2_0
executed!
j_i: 2_1
executed!
j_i: 2_2
executed!
j_i: 2_3
executed!
j_i: 2_4
j_i: 3_0
executed!
j_i: 3_1
executed!
j_i: 3_2
executed!
j_i: 3_3
executed!
j_i: 3_4
j_i: 4_0
executed!
j_i: 4_1
executed!
j_i: 4_2
executed!
j_i: 4_3
executed!
j_i: 4_4
j_i: 5_0
executed!
j_i: 5_1
executed!
j_i: 5_2
executed!
j_i: 5_3
executed!
j_i: 5_4
j_i: 6_0
executed!
j_i: 6_1
executed!
j_i: 6_2
executed!
j_i: 6_3
executed!
j_i: 6_4
j_i: 7_0
executed!
j_i: 7_1
executed!
j_i: 7_2
executed!
j_i: 7_3
executed!
j_i: 7_4
j_i: 8_0
executed!
j_i: 8_1
executed!
j_i: 8_2
executed!
j_i: 8_3
executed!
j_i: 8_4
j_i: 9_0
executed!
j_i: 9_1
executed!
j_i: 9_2
executed!
j_i: 9_3
executed!
j_i: 9_4

RETURN的输出为：

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j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4

CONTINUE的输出为：

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j_i: 0_0
executed!
j_i: 0_1
executed!
j_i: 0_2
executed!
j_i: 0_3
executed!
j_i: 0_4
j_i: 0_5
j_i: 0_6
j_i: 0_7
j_i: 0_8
j_i: 0_9
j_i: 1_0
executed!
j_i: 1_1
executed!
j_i: 1_2
executed!
j_i: 1_3
executed!
j_i: 1_4
j_i: 1_5
j_i: 1_6
j_i: 1_7
j_i: 1_8
j_i: 1_9
j_i: 2_0
executed!
j_i: 2_1
executed!
j_i: 2_2
executed!
j_i: 2_3
executed!
j_i: 2_4
j_i: 2_5
j_i: 2_6
j_i: 2_7
j_i: 2_8
j_i: 2_9
j_i: 3_0
executed!
j_i: 3_1
executed!
j_i: 3_2
executed!
j_i: 3_3
executed!
j_i: 3_4
j_i: 3_5
j_i: 3_6
j_i: 3_7
j_i: 3_8
j_i: 3_9
j_i: 4_0
executed!
j_i: 4_1
executed!
j_i: 4_2
executed!
j_i: 4_3
executed!
j_i: 4_4
j_i: 4_5
j_i: 4_6
j_i: 4_7
j_i: 4_8
j_i: 4_9
j_i: 5_0
executed!
j_i: 5_1
executed!
j_i: 5_2
executed!
j_i: 5_3
executed!
j_i: 5_4
j_i: 5_5
j_i: 5_6
j_i: 5_7
j_i: 5_8
j_i: 5_9
j_i: 6_0
executed!
j_i: 6_1
executed!
j_i: 6_2
executed!
j_i: 6_3
executed!
j_i: 6_4
j_i: 6_5
j_i: 6_6
j_i: 6_7
j_i: 6_8
j_i: 6_9
j_i: 7_0
executed!
j_i: 7_1
executed!
j_i: 7_2
executed!
j_i: 7_3
executed!
j_i: 7_4
j_i: 7_5
j_i: 7_6
j_i: 7_7
j_i: 7_8
j_i: 7_9
j_i: 8_0
executed!
j_i: 8_1
executed!
j_i: 8_2
executed!
j_i: 8_3
executed!
j_i: 8_4
j_i: 8_5
j_i: 8_6
j_i: 8_7
j_i: 8_8
j_i: 8_9
j_i: 9_0
executed!
j_i: 9_1
executed!
j_i: 9_2
executed!
j_i: 9_3
executed!
j_i: 9_4
j_i: 9_5
j_i: 9_6
j_i: 9_7
j_i: 9_8
j_i: 9_9 参考技术C

你说的是continue吧，在循环内结束，然后进行下一次循环，下面是我写的例子，你看一下。

for i in range(10):
    #如果是2的倍数，那么不执行接下来的动作，你改成break试一下，会有别的情况
    if i % 2 == 0:
        continue
    #打印
    print i
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本回答被提问者和网友采纳 参考技术D # encoding: utf-8

import os
import glob
import shutil

backuptarget = r'E:\backup'
srcpath = r'D:\workspace\Projects\DNCSS\python'

def target_mapper(fullpath):
''' 根据文件名映射目标文件名
path, fname = os.path.split(fullpath)
return os.path.join(backuptarget, fname)

for f in glob.glob(os.path.join(srcpath,'log', '*.log')):
try:
shutil.move(f, target_mapper(f))
except:
continue # 再循环中捕获到异常后要求继续即可