HDU-5510 Bazinga

Posted 2020-08-09 Kiven#5197

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 2390    Accepted Submission(s): 746

 

Problem Description

Ladies and gentlemen, please sit up straight.
Don\'t tilt your head. I\'m serious.

For n given strings S1,S2,⋯,Sn, labelled from 1 to n, you should find the largest i (1≤i≤n) such that there exists an integer j (1≤j<i) and Sj is not a substring of Si.

A substring of a string Si is another string that occurs in Si. For example, ``ruiz" is a substring of ``ruizhang", and ``rzhang" is not a substring of ``ruizhang".

 

 

Input

The first line contains an integer t (1≤t≤50) which is the number of test cases.
For each test case, the first line is the positive integer n (1≤n≤500) and in the following n lines list are the strings S1,S2,⋯,Sn.
All strings are given in lower-case letters and strings are no longer than 2000 letters.

 

 

Output

For each test case, output the largest label you get. If it does not exist, output −1.

 

 

Sample Input

4

5

ab

abc

zabc

abcd

zabcd

4

you

lovinyou

aboutlovinyou

allaboutlovinyou

5

de

def

abcd

abcde

abcdef

3

a

ba

ccc

 

Sample Output

Case #1: 4

Case #2: -1

Case #3: 4

Case #4: 3

 

题意：

求i最大的且其前无子串的字符串，若无则输出-1。

 

我们运用了求子串函数strstr();   关于strstr();的介绍请见：http://www.cnblogs.com/Kiven5197/p/5869909.html

先找两个相邻 若找出不匹配的串再反向对比。

 

附AC代码：

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 
 4 //strstr();
 5 
 6 char s[510][2010];
 7 
 8 int main(){
 9     int t,n;
10     scanf("%d",&t);//cin>>t;
11     int ans=1;
12     while(t--){
13         scanf("%d",&n);//cin>>n;
14         for(int i=1;i<=n;i++){
15             scanf("%s",s[i]);//cin>>s[i];
16         }
17         int res=-1;
18         for(int i=n;i>0;i--){
19             if(!strstr(s[i],s[i-1])){
20                 res=max(i,res);
21                 for(int j=i+1;j<=n;j++){
22                     if(!strstr(s[j],s[i-1])){
23                         res=max(j,res);
24                     }
25                 }
26             }
27         }
28         printf("Case #%d: %d\\n",ans++,res);//cout<<"Case #"<<ans++<<": "<<res<<endl;
29     }
30     return 0;
31 }

 

这题第一发用的cin和coutT掉了..改成scanf printf就A了