用asp.net的json响应返回一个特定的视图。

Posted 2023-03-01

我正在创建一个asp.net web服务，我想使用一个带有儿子内容的html页面传递给它。我在控制器中有json数据，但当我返回时，我想指定哪个视图与json数据一起密封。

[HttpPost]
public async Task<IActionResult> Create(IFormFile postedFile)

    byte[] data;
    using (var br = new BinaryReader(postedFile.OpenReadStream()))
    
        data = br.ReadBytes((int)postedFile.OpenReadStream().Length);
    

    HttpContent fileContent = new ByteArrayContent(data);
    string uirWebAPI = _configuration.GetValue<string>("Api");

    using (var client = new HttpClient())
    
        using (var formData = new MultipartFormDataContent())
        
            formData.Add(fileContent, "file", "File");
            client.DefaultRequestHeaders.Add("blobPath", meshFilePath);
            // calling another API to do some processing and return a json response
            var response = client.PostAsync(uirWebAPI, formData).Result;
            if (response.IsSuccessStatusCode)
            
                using (Stream responseStream = await response.Content.ReadAsStreamAsync())
                
                    jsonMessage = new StreamReader(responseStream).ReadToEnd();
                
                var jsonString = await response.Content.ReadAsStringAsync();
                jsonObject = JsonConvert.DeserializeObject<object>(jsonString);
            
            else
            
                return null;
            
        
    

    ViewData["jsonData"] = jsonString;
    return View();

我想做这样的事情。

var jsonData = jsonObject 
return View("myHTMLpage", jsonData);

如何做到这一点与ASP.NET MVC？

答案

你可以创建自定义的ActionResult作为 JsonNetResult

public class JsonNetResult : ActionResult

    public Encoding ContentEncoding  get; set; 
    public string ContentType  get; set; 
    public object Data  get; set; 

    public JsonSerializerSettings SerializerSettings  get; set; 
    public Formatting Formatting  get; set; 

    public JsonNetResult() 
        SerializerSettings = new JsonSerializerSettings();
    

    public override void ExecuteResult( ControllerContext context ) 
        if ( context == null )
            throw new ArgumentNullException( "context" );

        HttpResponseBase response = context.HttpContext.Response;

        response.ContentType = !string.IsNullOrEmpty( ContentType )
            ? ContentType
            : "application/json";

        if ( ContentEncoding != null )
            response.ContentEncoding = ContentEncoding;

        if ( Data != null ) 
            JsonTextWriter writer = new JsonTextWriter( response.Output )  Formatting = Formatting ;

            JsonSerializer serializer = JsonSerializer.Create( SerializerSettings );
            serializer.Serialize( writer, Data );

            writer.Flush();