无法使用esp32和Arduinojson从Googlesheet获取数据

Posted 2023-02-28

我是esp32的新手，现在我正尝试使用ArduinoJson获取数据，在我的Googlesheet中，“ A1”有一个数字，我想让esp32来获取它，我将googlesheet发送到互联网并使用网址：https://spreadsheets.google.com/feeds/cells/1RICYSv0y0wEEu-PhcCL45jZmh7DlFSAsbW8Bie0inbA/1/public/values?alt=json&range=A1。而我的电话号码位于对象>提要>条目> 0>内容> $ t。

[这里是问题：当我使用esp32获取此json数据时，即使我的esp32已连接到googlesheet，我也无法获取它

如果需要，这是我的完整代码：

#include <ArduinoJson.h>
#include <WiFi.h>
#include <SPI.h>

WiFiClient client;

const char* ssid = "wwwwwwwww";
const char* password = "wwwwwwww";
const char* server = "spreadsheets.google.com";
const char* resource = "/feeds/cells/1RICYSv0y0wEEu-PhcCL45jZmh7DlFSAsbW8Bie0inbA/1/public/values?alt=json&range=A1";


const unsigned long HTTP_TIMEOUT = 10000;  // max respone time from server
const size_t MAX_CONTENT_SIZE = 1024;       // max size of the HTTP response

byte mac[] = 0xDE, 0xAD, 0xBE, 0xEF, 0xFE, 0xED;

struct clientData 
  char item[8];
;


void setup() 
  Serial.begin(9600);
  while (!Serial) 

  
  Serial.println("Serial ready");
  Serial.print("Connecting to wifi: ");
  Serial.println(ssid);

  WiFi.begin(ssid, password);
  while (WiFi.status() != WL_CONNECTED) 
    delay(500);
    Serial.print(".");
  
  Serial.println("");
  Serial.println("WiFi connected");
  Serial.println("IP address: ");
  Serial.println(WiFi.localIP());



void loop() 
  if(connect(server)) 
    if(sendRequest(server, resource) && skipResponseHeaders()) 
      clientData clientData;
      if(readReponseContent(&clientData)) 
        printclientData(&clientData);
      
    
  
  disconnect();
  wait();



bool connect(const char* hostName) 
  Serial.print("Connect to ");
  Serial.println(hostName);

  bool ok = client.connect(hostName, 80);

  Serial.println(ok ? "Connected" : "Connection Failed!");
  return ok;



bool sendRequest(const char* host, const char* resource) 
  Serial.print("GET ");
  Serial.println(resource);

  client.print("GET ");
  client.print(resource);
  client.println(" HTTP/1.1");
  client.print("Host: ");
  client.println(host);
  client.println("Connection: close");
  client.println();

  return true;


bool skipResponseHeaders() 
  // HTTP headers end with an empty line
  char endOfHeaders[] = "\r\n\r\n";

  client.setTimeout(HTTP_TIMEOUT);
  bool ok = client.find(endOfHeaders);

  if (!ok) 
    Serial.println("No response or invalid response!");
  
  return ok;



bool readReponseContent(struct clientData* clientData) 
  const size_t bufferSize = 5*JSON_ARRAY_SIZE(1) + 
  JSON_ARRAY_SIZE(5) + 10*JSON_OBJECT_SIZE(1) + 
  6*JSON_OBJECT_SIZE(2) + 7*JSON_OBJECT_SIZE(3) + 
  JSON_OBJECT_SIZE(4) + JSON_OBJECT_SIZE(7) + JSON_OBJECT_SIZE(15);
  DynamicJsonBuffer jsonBuffer(bufferSize);

  JsonObject& root = jsonBuffer.parseObject(client);

  if (!root.success()) 
    Serial.println("JSON parsing failed!");
    return false;
  

  strcpy(clientData->item, root["feed"]["entry"][0]["content"]["$t"]);

  return true;



void printclientData(const struct clientData* clientData) 
  Serial.print("Time = ");
  Serial.println(clientData->item);



void disconnect() 
  Serial.println("Disconnect");
  client.stop();


void wait() 
  Serial.println("Wait 20 seconds");
  delay(20000);

串行输出：

Connecting to wifi: wwwwwwwwww
..
WiFi connected
IP address: 
xxx.xxx.x.xx
Connect to spreadsheets.google.com
Connected
GET /feeds/cells/1RICYSv0y0wEEu-PhcCL45jZmh7DlFSAsbW8Bie0inbA/1/public/values?alt=json&range=A1
JSON parsing failed!
Disconnect
Wait 20 seconds

答案

如果我基于您的json输出并使用ArduinoJson Assistant计算bufferSize，我会得到这个：

const size_t capacity = 5*JSON_ARRAY_SIZE(1) + JSON_ARRAY_SIZE(5) + 10*JSON_OBJECT_SIZE(1) + 6*JSON_OBJECT_SIZE(2) + 7*JSON_OBJECT_SIZE(3) + JSON_OBJECT_SIZE(4) + JSON_OBJECT_SIZE(7) + JSON_OBJECT_SIZE(15) + 2270;

末尾省略了+ 2270？您解析的json失败，因为您的bufferSize不足2270个字节（即，您的bufferSize太小）。

Updte

我没有尝试调试您的代码，但是我可以方便地使用此Web客户端，因此我可以运行它，并且对我有用。

我的代码基于ESP32 Arduino Core的HTTPClient，您可以在https://github.com/espressif/arduino-esp32/tree/master/libraries/HTTPClient上进一步了解它。它基于您使用的Arduino Wificlient，但更容易获得负载。我建议您使用它。

我在代码中添加了ArduinoJson，但是我的是基于v6语法的，如果仍然觉得使用v5更容易，可以将其转换为v5语法。顺便说一句，json文档包含Unicode，我必须在程序的顶部添加#define ARDUINOJSON_DECODE_UNICODE 1才能使其正常工作，否则我将得到deserializationerror为NotSupported。

#define ARDUINOJSON_DECODE_UNICODE 1
#include <ArduinoJson.h>
#include <WiFi.h>
#include <HTTPClient.h>

HTTPClient http;

const char* ssid = "your_SSID";
const char* password = "your_password";

const char* url = "https://spreadsheets.google.com/feeds/cells/1RICYSv0y0wEEu-PhcCL45jZmh7DlFSAsbW8Bie0inbA/1/public/values?alt=json&range=A1";

void setup() 
  Serial.begin(115200);
  while (!Serial) 
  Serial.print("Connecting to wifi: "); Serial.println(ssid);

  WiFi.begin(ssid, password);
  while (WiFi.status() != WL_CONNECTED) 
    delay(200);
    Serial.print(".");
  
  Serial.println();
  Serial.print("IP address: "); Serial.println(WiFi.localIP());

  http.begin(url); 
  int httpCode = http.GET();  //send GET request

  if (!httpCode == 200) 
    Serial.print("Error on HTTP request: ");
    Serial.println(httpCode);
   else 
    String payload = http.getString();
    Serial.println(httpCode);
    Serial.println(payload);

    // the following is based on ArduinoJson v6 API
    StaticJsonDocument<4000> doc;
    DeserializationError err = deserializeJson(doc, payload);
    if (err) 
      Serial.print("deserialization error ");
      Serial.println(err.c_str());
    

    JsonObject feed = doc["feed"];
    const char* clientData = feed["entry"][0]["content"]["$t"];
    Serial.println(clientData);
  
  http.end(); //Free the resources




void loop()