使用列作为函数的输入参数并将结果添加到表中

Posted 2023-02-24

[ConvertIPToLong是一个函数，我试图将＃test1中的network列用作变量@cidrIP。我的结果应具有network列以及LowRange和HighRange列。

SELECT * 
from #test1 as t1


Declare @CidrIP varchar(20)
Set @CidrIP = (select [network] from #test1)

Select dbo.[ConvertIPToLong](left(@CidrIP, patindex('%/%' , @CidrIP) - 1)) & (cast(4294967295 as bigint) ^ (Power(2, 32 - Cast(substring(@CidrIP, patindex('%/%' , @CidrIP) + 1, 2) as int)) - 1)) as LowRange
       dbo.[ConvertIPToLong](left(@CidrIP, patindex('%/%' , @CidrIP) - 1)) & (cast(4294967295 as bigint) ^ (Power(2, 32 - Cast(substring(@CidrIP, patindex('%/%' , @CidrIP) + 1, 2) as int)) - 1)) + (Power(2, 32 - Cast(substring(@CidrIP, patindex('%/%' , @CidrIP) + 1, 2) as int)) - 1) as HighRange 

答案

如果我了解你，我希望这样的事情可以工作：

Select dbo.[ConvertIPToLong](left([network], patindex('%/%' , [network]) - 1)) & (cast(4294967295 as bigint) ^ (Power(2, 32 - Cast(substring([network], patindex('%/%' , [network]) + 1, 2) as int)) - 1)) as LowRange
       dbo.[ConvertIPToLong](left([network], patindex('%/%' , [network]) - 1)) & (cast(4294967295 as bigint) ^ (Power(2, 32 - Cast(substring([network], patindex('%/%' , [network]) + 1, 2) as int)) - 1)) + (Power(2, 32 - Cast(substring([network], patindex('%/%' , [network]) + 1, 2) as int)) - 1) as HighRange 
from #test1