根据不同的id开头从数据库更改密码
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我有3张桌子(医生,护士,病人),他们都有不同的身份证明开始,医生身份从101开始,护士从102开始,患者从200开始。我想根据他们的id的开头更改密码。在我的JFrame中我有5个JComponents,4个Jtextfields,1个Jbutton 1 Jtextfields用于id(name:idField)1个Jtextfields用于当前密码(name:currentPass)2个Jtextfields用于新密码(name:newPass1,newPass2)1个Jbutton for动作(名称:changeButton)
我在我的代码中做了两种不同的方式,但两者都不适用于我。你能帮我解决这个问题吗?
第一种方式:
private void changeButtonActionPerformed(java.awt.event.ActionEvent evt)
id=idField.getText();
newpass1=newPass1.getText();
newpass2=newPass2.getText();
try
con = DriverManager.getConnection("jdbc:derby://localhost:1527/hj", "xxx", "xxx");
st = con.createStatement();
if (newpass1.equals(newpass2))
ResultSet rs = st.executeQuery("update patient set patient_Password="+ newpass1 +" where patient_Id="+id+" and patient_Id like '200%'");
JOptionPane.showMessageDialog(this , "Successfully changed", "Patient password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
ResultSet rs1 = st.executeQuery("update Nurse set nurse_password="+ newpass1 +" where nurse_id="+id+" and nurse_id like '102%'");
JOptionPane.showMessageDialog(this , "Successfully changed", "Nurse password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
ResultSet rs2 = st.executeQuery("update doctor set doctor_password="+ newpass1 +" where doctor_id="+id+" and doctor_id like '101%'");
JOptionPane.showMessageDialog(this , "Successfully changed", "Doctor password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
else
JOptionPane.showMessageDialog(this , "Not equal", "Your new passwords are not equal!! , try again",JOptionPane.ERROR_MESSAGE );
catch (Exception x)
JOptionPane.showMessageDialog(this, x.getStackTrace());
第二种方式:
private void changeButtonActionPerformed(java.awt.event.ActionEvent evt)
id=idField.getText();
newpass1=newPass1.getText();
newpass2=newPass2.getText();
try
con = DriverManager.getConnection("jdbc:derby://localhost:1527/hj", "xxx", "xxx");
st = con.createStatement();
if (newpass1.equals(newpass2))
if (id.startsWith("200"))
ResultSet rs = st.executeQuery("update patient set patient_Password="+ newpass1 +" where patient_Id="+id+"");
JOptionPane.showMessageDialog(this , "Successfully changed", "Patient password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
else if (id.startsWith("102"))
ResultSet rs = st.executeQuery("update Nurse set nurse_password="+ newpass1 +" where nurse_id="+id+"");
JOptionPane.showMessageDialog(this , "Successfully changed", "Nurse password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
else if (id.startsWith("101"))
ResultSet rs = st.executeQuery("update doctor set doctor_password="+ newpass1 +" where doctor_id="+id+"");
JOptionPane.showMessageDialog(this , "Successfully changed", "Doctor password successfuly changed !",JOptionPane.PLAIN_MESSAGE);
else
JOptionPane.showMessageDialog(this , "Not equal", "Your new passwords are not equal!! , try again",JOptionPane.ERROR_MESSAGE );
catch (Exception x)
JOptionPane.showMessageDialog(this, x.getStackTrace());
答案
请使用PreparedStatement
!
if (id.startsWith("200"))
try (PreparedStatement pstmt = conn.prepareStatement("UPDATE patient SET patient_passwort=? WHERE patient_id=?");)
pstmt.setString(1, newpass1);
pstmt.setString(2, id);
int rows = pstmt.executeUpdate();
JOptionPane.showMessageDialog(this , "Successfully changed",
"Patient password successfuly changed! (updated rows: "+rows+")", JOptionPane.PLAIN_MESSAGE);
通过连接查询,您将获得update patient set patient_Password=abcdefghi where patient_Id=200340 and patient_Id like '200%'
。未引用新密码(此处为abcdefghi
),这对于查询中的字符串是必需的。 patient_id
也没有引用,但它可能是一个数字字段,不得引用。
BTW:
- 不需要查询部分
patient_id like '200%'
。 - 您应该关闭所有PreparedStatement / Statement实例,这可以通过使用try-with-resources(
try (PreparedStatement xxx = ...) ... your code // closes automatically
)来完成。同样适用于Connection
和ResultSet
。 - 因为
id
是一个整数,你可能想要这样使用它:int updId = Integer.parseInt(id); ... pstmt.setInt(2, updId); ...
提普:如果你使用Apache commons-dbutils,你会更加轻松。例如org.apache.commons.dbutils.QueryRunner
QueryRunner r = new QueryRunner();
int rows = r.update(conn,
"UPDATE patient SET patient_passwort=? WHERE patient_id=?",
newpass1, id);
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