需要将socket.io类更改为单例

Posted 2023-02-20

使socket.io成为单例的最佳方法是什么？这里我有三个文件，我需要在user.mjs

中使用socket.io方法

socket.mjs

class socketBusiness extends baseBusiness 
  //io = null;
  //connectedUsers = 
  constructor(io) 
    super(io);
    this.io = io;
    this.connectedUsers = ;
    this.addUserRef= ; 
    this.bindEvents();
  

  unBindEvents() 
    this.io.off("connection", this.onConnection);
  

  onConnection(socket) 
    let _io = this.io;
    let socketId = socket.id;
    let transport = socket.conn.transport.name;
    let address = socket.handshake.address;

    logHelper.logInfo(
      `a user connected with transport: $transport, ip: $address`
    );

    //socket.broadcast.emit('hi');

    socket.on("disconnect", reason => 
    );

    socket.on("chat message", function(msg) 
    );
  
 addUserRef(userId, cstId) 

      let arr = this.addUserRef[cstId] || [];
      if (arr.indexOf(cstId) < 0) 
        arr.push(cstId);
      
      this.addUserRef[userId] = arr; 
  

export default socketBusiness;

user.mjs

const socket = require("socket.mjs)
export async function addCst(req, res) 
socket.addUserRef(req.id,req.cstId)

我如何访问socket.io方法？任何帮助将不胜感激

www.mjs

import socket from '../socket.mjs';


var server = createServer(app);
var io = new SocketServer(server, )
var sb = new socketBusiness(io);

答案

导出实例：

 export default new socketBusiness;