我如何基于Awk中另一列中的值求和列中的值

Posted 2023-02-03

INPUT：

TT,SS,ECID,CDID,ODID,Symbol,Side,LastQty,LastPx,CumQty,AvgPx, 
"20191008-13:32:52","RO","0284","378MT","r7ot","SPD","1","100","290.67","400","290.67", 
"20191008-13:33:13","RO","02DJ","378MT","r7o","SPD","1","100","290.68","2248","290.655", 
"20191008-13:33:26","RO","FATS","378MTA","r7ot","PDF","1","100","290.92","2751","290.608",

输出应为：

SPD 200
PDF 100

尝试使用但不起作用

$ awk 'a[$3]+=$4ENDfor(i in a) print i,a[i]' file

答案

EDIT2：由于OP具有旧的awk，其中FPAT不存在，所以根据示例，我在代码中添加了以下代码。

awk -F, 'gsub(/\r/,"") FNR>1gsub(/"/,"",$8);gsub(/"/,"",$6);a[$6]+=$8 ENDfor(i in a)print i,a[i] | "sort -k1"' Input_file

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EDIT：由于OP完全更改了Input_file，因此现在添加此解决方案。用GNU awk编写和测试。

awk -v FPAT='[^,]*|"[^"]+"' '
gsub(/\r/,"")
FNR>1
  gsub(/"/,"",$8)
  gsub(/"/,"",$6)
  a[$6]+=$8

END
  for(i in a)
    print i,a[i]
  

'   Input_file

或按字母顺序对输出进行排序，请尝试以下。

awk -v FPAT='[^,]*|"[^"]+"' 'gsub(/\r/,"") FNR>1gsub(/"/,"",$8);gsub(/"/,"",$6);a[$6]+=$8 ENDfor(i in a)print i,a[i] | "sort -k1"'  Input_file

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[亲爱的，您的方法存在的问题是，您尚未在代码中将字段分隔符设置为,，但是Input_file的分隔符为,，因此它根本没有$3，因此无法正常工作。您可以尝试以下吗？

awk -F"[[:space:]]*,[[:space:]]*" 'FNR>1a[$3]+=$4 ENDfor(i in a)print i,a[i]' Input_file

PS：感谢oguz ismail通知了字段分隔符集。