仅使用PHP导出MySQL数据库[关闭]
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有人有一个将mysql数据库导出到.sql文件的教程。我没有shell访问权限所以我不能使用exec我找到了这个网址：http://davidwalsh.name/backup-mysql-database-php但我查看了代码并且这段代码很旧而且编写得不好。我查看了互联网，但对于大多数教程我需要shell访问，其余的已经过时了。
提前致谢。
答案
使用php脚本导出数据库的最佳方法。
或者添加特定表的第五个参数（数组）：array("mytable1","mytable2","mytable3")用于多个表
<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlUserName = "Your Username";
$mysqlPassword = "Your Password";
$mysqlHostName = "Your Host";
$DbName = "Your Database Name here";
$backup_name = "mybackup.sql";
$tables = "Your tables";
//or add 5th parameter(array) of specific tables: array("mytable1","mytable2","mytable3") for multiple tables
Export_Database($mysqlHostName,$mysqlUserName,$mysqlPassword,$DbName, $tables=false, $backup_name=false );
function Export_Database($host,$user,$pass,$name, $tables=false, $backup_name=false )
$mysqli = new mysqli($host,$user,$pass,$name);
$mysqli->select_db($name);
$mysqli->query("SET NAMES 'utf8'");
$queryTables = $mysqli->query('SHOW TABLES');
while($row = $queryTables->fetch_row())
$target_tables[] = $row[0];
if($tables !== false)
$target_tables = array_intersect( $target_tables, $tables);
foreach($target_tables as $table)
$result = $mysqli->query('SELECT * FROM '.$table);
$fields_amount = $result->field_count;
$rows_num=$mysqli->affected_rows;
$res = $mysqli->query('SHOW CREATE TABLE '.$table);
$TableMLine = $res->fetch_row();
$content = (!isset($content) ? '' : $content) . "\n\n".$TableMLine[1].";\n\n";
for ($i = 0, $st_counter = 0; $i < $fields_amount; $i++, $st_counter=0)
while($row = $result->fetch_row())
//when started (and every after 100 command cycle):
if ($st_counter%100 == 0 || $st_counter == 0 )
$content .= "\nINSERT INTO ".$table." VALUES";
$content .= "\n(";
for($j=0; $j<$fields_amount; $j++)
$row[$j] = str_replace("\n","\\n", addslashes($row[$j]) );
if (isset($row[$j]))
$content .= '"'.$row[$j].'"' ;
else
$content .= '""';
if ($j<($fields_amount-1))
$content.= ',';
$content .=")";
//every after 100 command cycle [or at last line] ....p.s. but should be inserted 1 cycle eariler
if ( (($st_counter+1)%100==0 && $st_counter!=0) || $st_counter+1==$rows_num)
$content .= ";";
else
$content .= ",";
$st_counter=$st_counter+1;
$content .="\n\n\n";
//$backup_name = $backup_name ? $backup_name : $name."___(".date('H-i-s')."_".date('d-m-Y').")__rand".rand(1,11111111).".sql";
$backup_name = $backup_name ? $backup_name : $name.".sql";
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename=\"".$backup_name."\"");
echo $content; exit;
?>
另一答案
您可以使用此命令它或我100％
shell_exec注意：
exec('C:\\wamp\\bin\\mysql\\mysql5.6.17\\bin\\mysqldump.exe -uroot DatabaseName> c:\\database_backup.sql');
是mysqldump app的路径，检查你的电脑。
C:\\wamp\\bin\\mysql\\mysql5.6.17\\bin\\mysqldump.exe是-uroot
如果你的数据库受密码保护，那么在这个sentense -uUserName之后添加
另一答案
这个工具可能很有用，它是一个基于PHP的纯出口实用程序：https://github.com/2createStudio/shuttle-export
另一答案
请尝试以下方法。
从PHP文件执行数据库备份查询。下面是使用SELECT INTO OUTFILE查询创建表备份的示例：
<?php
$DB_HOST = "localhost";
$DB_USER = "xxx";
$DB_PASS = "xxx";
$DB_NAME = "xxx";
$con = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if($con->connect_errno > 0)
die('Connection failed [' . $con->connect_error . ']');
$tableName = 'yourtable';
$backupFile = 'backup/yourtable.sql';
$query = "SELECT * INTO OUTFILE '$backupFile' FROM $tableName";
$result = mysqli_query($con,$query);
?>
要恢复备份，您只需运行LOAD DATA INFILE查询，如下所示：
<?php
$DB_HOST = "localhost";
$DB_USER = "xxx";
$DB_PASS = "xxx";
$DB_NAME = "xxx";
$con = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if($con->connect_errno > 0)
die('Connection failed [' . $con->connect_error . ']');
$tableName = 'yourtable';
$backupFile = 'yourtable.sql';
$query = "LOAD DATA INFILE 'backupFile' INTO TABLE $tableName";
$result = mysqli_query($con,$query);
?>
另一答案
在* nix系统中，使用WHICH命令显示mysqldump的位置，试试这个：
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'password';
$dbname = 'test';
$mysqldump=exec('which mysqldump');
$command = "$mysqldump --opt -h $dbhost -u $dbuser -p $dbpass $dbname > $dbname.sql";
exec($command);
?>
另一答案
<?php
$dbhost = 'localhost:3036';
$dbuser = 'root';
$dbpass = 'rootpassword';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
die('Could not connect: ' . mysql_error());
$table_name = "employee";
$backup_file = "/tmp/employee.sql";
$sql = "SELECT * INTO OUTFILE '$backup_file' FROM $table_name";
mysql_select_db('test_db');
$retval = mysql_query( $sql, $conn );
if(! $retval )
die('Could not take data backup: ' . mysql_error());
echo "Backedup data successfully\n";
mysql_close($conn);
?>
另一答案
我建议你做以下事情，
<?php
function EXPORT_TABLES($host, $user, $pass, $name, $tables = false, $backup_name = false)
$mysqli = new mysqli($host, $user, $pass, $name);
$mysqli->select_db($name);
$mysqli->query("SET NAMES 'utf8'");
$queryTables = $mysqli->query('SHOW TABLES');
while ($row = $queryTables->fetch_row())
$target_tables[] = $row[0];
if ($tables !== false)
$target_tables = array_intersect($target_tables, $tables);
$content = "SET SQL_MODE = \"NO_AUTO_VALUE_ON_ZERO\";\r\nSET time_zone = \"+00:00\";\r\n\r\n\r\n/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;\r\n/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;\r\n/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;\r\n/*!40101 SET NAMES utf8 */;\r\n--Database: `" . $name . "`\r\n\r\n\r\n";
foreach ($target_tables as $table)
$result = $mysqli->query('SELECT * FROM ' . $table);
$fields_amount = $result->field_count;
$rows_num = $mysqli->affected_rows;
$res = $mysqli->query('SHOW CREATE TABLE ' . $table);
$TableMLine = $res->fetch_row();
$content .= "\n\n" . $TableMLine[1] . ";\n\n";
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