我想解析Gson信息但出现错误

Posted 2023-01-22

我正在尝试发送源和目标的数据。

public void sendPost(final SearchSendModel searchSendModel)
    //public void sendPost( String source, String destination)
        Call call = mAPIService.sendSearch(searchSendModel);
        //Call call = mAPIService.sendSearch(source, destination);
        call.enqueue(new Callback<SearchModel>() 
            @Override
            public void onResponse(Call<SearchModel> call, Response<SearchModel> response) 
                Toast.makeText(Search.this, " Responce " +response.body(), Toast.LENGTH_SHORT).show();
                Log.v("Responce", "Responce "+response.body());
                if (response.isSuccessful())
                    SearchModel searchResponse = response.body();
                    assert searchResponse != null;

                    String content = "";
                    content += "Code: " +response.code() +"\n";
                    content += "vech_id: " + searchResponse.getVechId() +"\n";
                    content += "model_no: " + searchResponse.getModelNo() +"\n";
                    content += "reg_no: " +searchResponse.getRegNo() +"\n";
                    content += "delivery_start_date: " +searchResponse.getDeliveryStartDate() +"\n";
                    content += "delivery_end_date: " +searchResponse.getDeliveryEndDate() +"\n";
                    content += "full_percent: " +searchResponse.getFullPercent() +"\n";
                    content += "approval_status: " +searchResponse.getApprovalStatus() +"\n";
                    content +="source: " +searchResponse.getSource() +"\n";
                    content += "destination: " +searchResponse.getDestination() +"\n\n";
                    Toast.makeText(getApplicationContext(),content,Toast.LENGTH_LONG).show();

                    searchModelList.add(searchResponse);
                else 
                    Toast.makeText(getApplicationContext(),"Something is error",Toast.LENGTH_SHORT).show();
                

这是我期望的Json回应：

[
    
        "vech_id": "30",
        "model_no": "8956",
        "reg_no": "98765",
        "delivery_start_date": "2020-03-18",
        "delivery_end_date": "2020-06-24",
        "full_percent": "0.14",
        "approval_status": "1",
        "source": "ranchi",
        "destination": "garwah"
    
]

API的接口是：

@POST("search_vehicle.php")
    @FormUrlEncoded
    Call<SearchSendModel> sendSearch(@Body SearchSendModel searchSendModel);

SearchSendModel.java

public class SearchSendModel 

    public SearchSendModel(String source, String destination) 
        this.source = source;
        this.destination = destination;
    

    @SerializedName("source")
    private String source;

    @SerializedName("destination")
    private String destination;

    public String getSource() 
        return source;
    

    public String getDestination() 
        return destination;
    

但是我总是会收到此错误：java.lang.IllegalStateException：预期为BEGIN_OBJECT，但在第2行第2列2路径处为BEGIN_ARRAY $

答案

我认为您的onResponse应该使用List<SearchModel>而不是SearchModel。您的响应格式为数组。