如何使用php [关闭]并行打印数组

Posted 2023-01-20

我有一个名为images的表，其中2列：user_id＆image_path，user_id的值=> 1,1,2,2,3，image_path的值=> abc,xyz,qwe,asd,wes

换句话说（我需要使用php进行以下输出）：

user_id:1
image_path:abc
           xyz

user_id:2
image_path:qwe
           asd

user_id:3
image_path:wes

代码是：

$sqlb="SELECT * FROM image"; 
$resultb=mysqli_query($conn,$sqlb); 
if($resultb->num_rows>0)  $
    i=0; 
    while($rowb=$resultb->fetch_assoc())  
        $user_id[$i]['user_id']=$rowb['user_id']; 
        $user_id[$i]['image_path']=array($rowb['image_path']); 
        $i++; 
     
    $response['session']=TRUE; 
    $response['session_status']=TRUE; 
    $response['Msg']="successfully users data find";
    $response['user_detail']=$user_id; 
    echo json_encode($response); 
 

答案

使结果成为一个由用户ID键控的关联数组。然后，很容易收集相同用户ID的所有图像路径。

$result = array();
while ($rowb = $result->fetch_assoc()) 
    $userid = $rowb['user_id'];
    if (!isset($result[$userid])) 
        $result[$userid] = array('user_id' => $userid, 'image_path' => array());
    
    $result[$userid]['image_path'][] = $rowb['image_path'];

生成的JSON将如下所示：

    "1":  "user_id": 1, "image_path": ["abc", "xyz"],
    "2":  "user_id": 2, "image_path": ["qwe", "asd"],
    "3":  "user_id": 3, "image_path": ["wes"]