我们如何在Yii 2中的模块中创建单独的用户实例？

Posted 2023-01-17

我已经尝试了很多让用户通过我的模块登录。但总是失败。它既没有显示错误也没有登录到应用程序。到目前为止，我已经尝试过了。

我的module/moduleName/moduleName.php初始化函数是

public function init()

    parent::init();

    // custom initialization code goes here

    Yii::$app->set('user', [
        'class' => 'yii\web\User',
        'identityClass' => 'app\module\modulesName\models\UserTable',
        'enableAutoLogin' => false,
        'loginUrl' => ['moduleName/default/login'],
        'identityCookie' => ['name' => 'module', 'httpOnly' => true],
        'idParam' => 'id', //this is important !
    ]);

    Yii::$app->set('session', [
        'class' => 'yii\web\Session',
        'name' => '_adminSessionId',
    ]);

现在我在Loginform的app\module\moduleName\models\LoginForm是

<?php

namespace app\modules\moduleName\models;

use Yii;
use yii\base\Model;

/**
 * LoginForm is the model behind the login form.
 *
 * @property User|null $user This property is read-only.
 *
 */
class LoginForm extends Model

    public $username;
    public $password;
    public $rememberMe = true;

    private $_user = false;


    /**
     * @return array the validation rules.
     */
    public function rules()
    
        return [
            // username and password are both required
            [['username', 'password'], 'required'],
            // rememberMe must be a boolean value
            ['rememberMe', 'boolean'],
            // password is validated by validatePassword()
            ['password', 'validatePassword'],
        ];
    

    /**
     * Validates the password.
     * This method serves as the inline validation for password.
     *
     * @param string $attribute the attribute currently being validated
     * @param array $params the additional name-value pairs given in the rule
     */
    public function validatePassword($attribute, $params)
    
        if (!$this->hasErrors()) 
            $user = $this->getUser();

            if (!$user || !$user->validatePassword($this->password)) 
                $this->addError($attribute, 'Incorrect username or password.');
            
        
    

    /**
     * Logs in a user using the provided username and password.
     * @return bool whether the user is logged in successfully
     */
    public function login()
    
        if ($this->validate()) 
            return Yii::$app->user->login($this->getUser(), $this->rememberMe ? 3600*24*30 : 0);
        
        return false;
    

    /**
     * Finds user by [[username]]
     *
     * @return User|null
     */
    public function getUser()
    
        if ($this->_user === false) 
            $this->_user = UserTable::findByUsername($this->username);
        

        return $this->_user;
    

最后我在app\module\moduleName\models\UserTable登录的模型是

<?php

namespace app\modules\moduleName\models;

use Yii;

/**
 * @property integer $id
 * @property string $fullName
 * @property string $email
 * @property string $password
 * @property string $authkey
 * @property string $accessToken
 * @property integer $authStatus

 */
class UserTable extends \yii\db\ActiveRecord  implements \yii\web\IdentityInterface

    /**
     * @inheritdoc
     */
    public static function tableName()
    
        return 'usertable';
    

    /**
     * @inheritdoc
     */
    public function rules()
    
        return [
            [['fullName', 'email', 'password'], 'required'],
            [['authStatus'], 'integer'],
            [['fullName', 'email', 'password'], 'string', 'max' => 50],
            [['authkey', 'accessToken'], 'string', 'max' => 75],
            // [['fullName', 'password'], 'unique', 'targetAttribute' => ['fullName', 'password'], 'message' => 'The combination of Full Name and Password has already been taken.'],
        ];
    

    /**
     * @inheritdoc
     */
    public function attributeLabels()
    
        return [
            'id' => 'ID',
            'fullName' => 'Full Name',
            'email' => 'Email',
            'password' => 'Password',
            'authkey' => 'Authkey',
            'accessToken' => 'Access Token',
            'authStatus' => 'Auth Status',
        ];
    

    /**
     * @return \yii\db\ActiveQuery
     */

     // User login Codes

     public function getId()
    
        return $this->id;
    

    /**
     * @inheritdoc
     */
    public function getAuthKey()
    
        return $this->authKey;
    



    /**
     * @inheritdoc
     */
    public function validateAuthKey($authKey)
    
        return $this->authKey === $authKey;
    

    /**
     * Validates password
     *
     * @param string $password password to validate
     * @return bool if password provided is valid for current user
     */
    public function validatePassword($password)
    

    return $this->password ===($password);
    

    public static function findIdentity($id)
    
        return static::findOne($id);
    
    public static function findIdentityByAccessToken($token,$type=null)
    
        return $this->accessToken;
    
    public static function findbyUsername($uname)
    

        return self::find()->where(['email' => $uname])->one();
    

最后我的模块中的defaultcontroller是

public function actionIndex()

    if (!Yii::$app->user->isGuest)
        var_dump('a');
        exit();
        return $this->render('index');
     else 
      return $this->redirect(['login']);
    


public function actionLogin()
  
    if (!Yii::$app->user->isGuest) 
        return $this->goHome();
    

    $model = new LoginForm();
    if ($model->load(Yii::$app->request->post()) ) 
        return $this->redirect(['index']);
    
    return $this->render('login', [
        'model' => $model,
    ]);

我不知道应用程序是如何登录的。我已经尝试了3天了，我没有得到任何解决方案。它既没有显示错误也没有登录？如何在yii2中登录不同的用户实例？

答案

在模块目录中创建单独的config.php，然后添加它以将其注入到您的应用程序中。这是代码。只需配置config.php即可

return [
    'id' => 'api',
    'basePath' => dirname(__DIR__),
    //....
    'components' => [
       //..
        'user' => [
           //....
        ]
    ],
];

在你的模块类中就是这样做的。

public function init()

    parent::init();

    \Yii::configure($this, require __DIR__ . '/config.php');

就这样。